Eight members of the committee will be chosen from 15 senior and 10 junior students. 13.) If there must be 5 senior students, how many junior students will be chosen? A.) 1 B.) 2 C.) 3 D.) 7 14.) How will you represent the number of combinations in #13? A.) N = C (15, 8) B.) N = C (10, 8) C.) N = C (15, 8) C (15, 8) D.) N = C (15, 5) C (10, 3) 15.) In how many ways can the 8 members of the committee be chosen from 15 senior and 10 junior students if there must be 5 senior students? A.) 45 B.) 6,435 C.) 360,360 D.) 1.081,575

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Eight members of the committee will be chosen from 15 senior and 10 junior students.
13.) If there must be 5 senior students, how many junior students will be chosen?
A.) 1
B.) 2
C.) 3
D.) 7
14.) How will you represent the number of combinations in #13?
A.) N = C (15, 8)
B.) N = C (10, 8)
C.) N = C (15, 8) C (15, 8)
D.) N = C (15, 5) C (10, 3)
15.) In how many ways can the 8 members of the committee be chosen from 15 senior
and 10 junior students if there must be 5 senior students?
A.) 45
B.) 6,435
C.) 360,360
D.) 1,081,575
Transcribed Image Text:Eight members of the committee will be chosen from 15 senior and 10 junior students. 13.) If there must be 5 senior students, how many junior students will be chosen? A.) 1 B.) 2 C.) 3 D.) 7 14.) How will you represent the number of combinations in #13? A.) N = C (15, 8) B.) N = C (10, 8) C.) N = C (15, 8) C (15, 8) D.) N = C (15, 5) C (10, 3) 15.) In how many ways can the 8 members of the committee be chosen from 15 senior and 10 junior students if there must be 5 senior students? A.) 45 B.) 6,435 C.) 360,360 D.) 1,081,575
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