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Given; √ √ tex dx 2 Applying rationalizing substitution, find dx in terms (A) z dz 2+z² 2 z dz B z²+2 none of the choices (2z+z) dz z² D E z dz z²-2 - 8

Given; √ √ tex dx 2 Applying rationalizing substitution, find dx in terms (A) z dz 2+z² 2 z dz B z²+2 none of the choices (2z+z) dz z² D E z dz z²-2 - 8

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given; • √ √ tex dx 2 Applying rationalizing substitution, find dx in terms of z. z dz A 2+z² 2 z dz B z²+2 c) none of the choices (2z+z) dz D z² E z dz 2²-2 8
Transcribed Image Text:Given; • √ √ tex dx 2 Applying rationalizing substitution, find dx in terms of z. z dz A 2+z² 2 z dz B z²+2 c) none of the choices (2z+z) dz D z² E z dz 2²-2 8
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Evaluate √ 4ex dx 2 Use rationalizing substitution. A B 8 e²-2-2√2 Arctan- 1 ²/² √√e ² - 2 + c lex - 2 - 2V2 Arctan . ¹ ²/² √² ² - 2 + c C none one of the choices (D) e (ex-2) 1/2 √√8 Arctan ¹1/²/2 √e ² - 2 + C E) e (ex-2) 1/2-√√8 Arctan ¹ ²/2 √ √2 e ² − 4 + C 2e² -
Transcribed Image Text:Evaluate √ 4ex dx 2 Use rationalizing substitution. A B 8 e²-2-2√2 Arctan- 1 ²/² √√e ² - 2 + c lex - 2 - 2V2 Arctan . ¹ ²/² √² ² - 2 + c C none one of the choices (D) e (ex-2) 1/2 √√8 Arctan ¹1/²/2 √e ² - 2 + C E) e (ex-2) 1/2-√√8 Arctan ¹ ²/2 √ √2 e ² − 4 + C 2e² -
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