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Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron-flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created. OCCO O\\ ² = 0 + Но H* EXP HO CH₂ CH₂ CH₂ H C N O S CI Br I P F

Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron-flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created. OCCO O\\ ² = 0 + Но H* EXP HO CH₂ CH₂ CH₂ H C N O S CI Br I P F

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron-flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created. ? A + M [1] A 1. Submit C HO ME 1 H EXP. CONT. OA CH₂ Previous Answers Request Answer CH3 CH₂ H+ CH3 H C N O S CI Br | P F X Incorrect; Try Again; 5 attempts remaining Your mechanism is missing a key intermediate. Under acidic conditions, the carbonyl oxygen is protonated to make the carbonyl carbon more susceptible to further nucleophilic attack.
Transcribed Image Text:Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron-flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created. ? A + M [1] A 1. Submit C HO ME 1 H EXP. CONT. OA CH₂ Previous Answers Request Answer CH3 CH₂ H+ CH3 H C N O S CI Br | P F X Incorrect; Try Again; 5 attempts remaining Your mechanism is missing a key intermediate. Under acidic conditions, the carbonyl oxygen is protonated to make the carbonyl carbon more susceptible to further nucleophilic attack.
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