ederal Government Employee E-mail Use It has been reported that 74% of federal government employees use e-mail. If a sample of 220 federal overnment employees is selected, find the mean, variance, and standard deviation of the number who use e-mail. Round your answers to three decimal places. Part: 0/2 Part 1 of 2 (a) Find the mean. Mean: μ = X

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**Federal Government Employee E-mail Use**

It has been reported that 74% of federal government employees use e-mail. If a sample of 220 federal government employees is selected, find the mean, variance, and standard deviation of the number who use e-mail. Round your answers to three decimal places.

**Part: 0 / 2**

**Part 1 of 2**

(a) Find the mean.

Mean: μ = [Input Box] [X Button] [Reset Button]

---

### Instructions:

1. Use the reported percentage (74%) to calculate the mean number of employees using e-mail in the sample of 220.
2. Apply the formula for mean in a binomial distribution: Mean (μ) = n * p, where n = sample size and p = probability of success.
3. Round your answer to three decimal places.

This part of the exercise involves understanding and applying basic statistical formulas related to binomial distributions.
Transcribed Image Text:**Federal Government Employee E-mail Use** It has been reported that 74% of federal government employees use e-mail. If a sample of 220 federal government employees is selected, find the mean, variance, and standard deviation of the number who use e-mail. Round your answers to three decimal places. **Part: 0 / 2** **Part 1 of 2** (a) Find the mean. Mean: μ = [Input Box] [X Button] [Reset Button] --- ### Instructions: 1. Use the reported percentage (74%) to calculate the mean number of employees using e-mail in the sample of 220. 2. Apply the formula for mean in a binomial distribution: Mean (μ) = n * p, where n = sample size and p = probability of success. 3. Round your answer to three decimal places. This part of the exercise involves understanding and applying basic statistical formulas related to binomial distributions.
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n = 220 ,p =0.74

 

 

 

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