edback e average angular displacement is given by the slope of the secant. We calculate f(0.2) and f(1.8) and use these values d the average rate of change between 0.2 to 1.8 seconds: Thus, avg angular displacement = msecant f(0.2) 120e = f(1.8) 120e ≈44.280879 = (0.2-12)2 0.3 +40 1.80.2 (1.8-1.2)2 0.3 +40 ≈ 76.143305 f(t₁) -f(to) t₁- to 76.143305 44.280879 ≈19.914016 We note that the slope is positive, therefore, on average, between 0.2 and 1.8 seconds, the angular displacement is increasing at a rate of 19.914016 degrees/second. Save Quit & Save Back Next
edback e average angular displacement is given by the slope of the secant. We calculate f(0.2) and f(1.8) and use these values d the average rate of change between 0.2 to 1.8 seconds: Thus, avg angular displacement = msecant f(0.2) 120e = f(1.8) 120e ≈44.280879 = (0.2-12)2 0.3 +40 1.80.2 (1.8-1.2)2 0.3 +40 ≈ 76.143305 f(t₁) -f(to) t₁- to 76.143305 44.280879 ≈19.914016 We note that the slope is positive, therefore, on average, between 0.2 and 1.8 seconds, the angular displacement is increasing at a rate of 19.914016 degrees/second. Save Quit & Save Back Next
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How is the answer 44 and 76? Please show all work
Transcribed Image Text:edback
and the average rate of change between 0.2 to 1.8 seconds:
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