Gg.158. please help me idk what i am doing wrongWhat is the approximate concentration of free Al³+ ion at equilibrium when1.14x102 mol aluminum nitrate is added to 1.00 L of solution that is 1.270 Min F. For [AIF6]³-, K = 6.9×10¹9.[A1³+]= 2.48x10^-16 MWhat is the approximate concentration of free Cu* ion at equilibrium when1.43x10-2 mol copper(I) nitrate is added to 1.00 L of solution that is 1.270 Min CN. For [Cu(CN)₂], K₁= 1.0x1024.[Cu] = 7.66x10^-14 M

“Since you have posted multiple questions, we will provide the solution only to the first question…

ease help me idk what i am doing wrong What is the approximate concentration of free Al³+ ion at equilibrium when 1.14x102 mol aluminum nitrate is added to 1.00 L of solution that is 1.270 M in F. For [AIF6]³-, Kf = 6.9×10¹9. [A1³+] = = 2.48x10^-16 M

ease help me idk what i am doing wrong What is the approximate concentration of free Al³+ ion at equilibrium when 1.14x102 mol aluminum nitrate is added to 1.00 L of solution that is 1.270 M in F. For [AIF6]³-, Kf = 6.9×10¹9. [A1³+] = = 2.48x10^-16 M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Question

Gg.158.

please help me idk what i am doing wrong
What is the approximate concentration of free Al³+ ion at equilibrium when
1.14x102 mol aluminum nitrate is added to 1.00 L of solution that is 1.270 M
in F. For [AIF6]³-, K = 6.9×10¹9.
[A1³+]
= 2.48x10^-16 M
What is the approximate concentration of free Cu* ion at equilibrium when
1.43x10-2 mol copper(I) nitrate is added to 1.00 L of solution that is 1.270 M
in CN. For [Cu(CN)₂], K₁= 1.0x1024.
[Cu] = 7.66x10^-14 M

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