Earth has a mass of 5.97×1024 kg and a radius of 6.37×106 m. The period of Earth'srotation is 24 hours (i.e., it rotates on its axis once every 24 hours). Imagine that Earth iscompressed down to half of its current radius, while its angular momentum is conservedand it retains all of its mass. Treat the Earth as a solid sphere, whose moment of inertia isI ==MR?.initialfinal(a) What is the final rotation period, in hours?(b) What is the change in Earth's rotational kinetic energy during this process?Give your answer in units of Joules.GG

Given m=5.97x1024kg Initial radius R=6.37x106m Final radius r=R/2 Initial Time period T=24hr=24x60x60sec=86400sec Therefore initial angular speed is Now let's assume final time period is t, therefore final angular speed will be a). Now since the angular momentum is conserved therefore initial angular momentum must be equal to final angular momentum therefore This is the new time period.b). Now change in rotation energy is Here we need to put time period in unit of second. Therefore Putting all the values we get This is the change in rotation kinetic energy.

Answered: Earth has a mass of 5.97×1024 kg and a…