ear transformation from R4 to R5 and let T(e1) = -3 3 19 -5 |-5 and T(e4) : 2 %3| 21 10 -2 -7 3 8 =formation and compute T -4 6.

Q: 2 4 x + 8 d x (x+2) ³

A: This question is based on definite integral.

Q: 6-5(3x - 5 )= -14  is x =

A: Distribute -5 and combine like terms.

Q: Evaluate x³ 2x² +7 dx S x² Ox² - 2x - 72 +0 0²-2x - 1 + C X O2+2 +c+C -2+7ln x² + C -

A:

Q: Eliminate

A:

Q: divccun(B)=0

A:

Q: can u explain step 3 and how you got the values for 2H(t-1) and 4H(t-3) and H(t-1)+4H(t-3)

A: Given .Note: In the given problem  which should be

Q: 1 |(12x5 - 11)dx -1

A: ∫-1112x5-11 dx

Q: 5. Use the substitution method to evaluate r1 5xe32+2 dr. 0.

A: To determine the value of the integral.

Q: Evaluate 10s? – 5 - L-1 2 (s² + 1)(s² + 3)²

A:

Q: -3(2y-8)-y = 3(y-3)

A: We open the brackets and simplify the equations of both the sides( Left hand side and right hand…

Q: S L-₁ ((5 + 1)²) = eat + aebt (s Find a + b.

A: Inverse laplace transformation

Q: 6 Q3. Evaluate Σή=1 5n2 - 7n.

A:

Q: x + 3y = 1 -3x-3y=-15

A:

Q: Evaluate | x2 Q4. dx + 4x + 3

A: 4) To evaluate the integral

Q: why is it -d +e -f and not +d -e +f?

A:

Q: 1. Find (A-1 B-1), If 0 -2 1 A = [] and B = [ [²4] 0

A:

Q: 3y-6(y+z)+y

A: Distribute -6.

Q: 6 4. Find A: s²+4 R: r()

A:

Q: 16. When (2x- 3)' is subtracted from 5x, the result is x²-12x-9 2x - 12x + 9 3x + 12x-9 4) x + 12x +…

A: Given:         2x-32 is subtracted from 5x2 is    here 2x-32 is in the form of a-b2=a2+b2-2ab

Q: Evaluate (x – 3) Vx + 3 dx |

A: Given : Integral (x-3) √(x+3)

Q: S3 ¹(s²-2s+2)(s²+2s+2)· e. L-11 7

A: In this question, we need to find the inverse Laplace of the given function.

Q: c=5/9(f-32) for f

A:

Q: y (y18 -10y8) 5/8 3/8 11/8 ().

A:

Q: 4a² • 3a5 = (4 + 3)a² + 5 = 7a 7 %3D %3D

A: The solution are as follows

Q: (ANB) %3D 20<X S 30 OR

A: Question belongs to set theory.

Q: Evaluate L-1 s²+10s-2 (s+2) (s²-3))

A:

Q: (s+1)* (s+2)

A:

Q: (9) [xV1-2х dx

A:

Q: (3): Evaluate 3e -5e +8 dx

A: To evaluate the given integral

Q: Evaluate L-1 [6s-5' s²+95

A:

Q: (b). Apply the indicated operator 4²(x³ + 6x² + 2x). [CLO-1: LOL: C-3, PLO- 1].

A:

Q: Find (AB)-1, (3A)-1, and (A*)-' given that 1 2 5 3 -3 4 A-1 = 3 1 6. B-1 = 1 3 2 8 1 6. 1

A: Recall: AB-1 = B-1A-1 aA-1 =aA-1 ; where 'a' is any scalar. At-1 =A-1t

Q: 3(3x-1=4(3x+1)

A: In the given equation first we distribute 3 over the terms in the parentheses of the left hand side…

Q: 4tan(x)+8=0

A:

Q: Evaluate (5+2) d dx Select the correct response: 11 16 ¹¹+x+x+C x + 4x + C 3 16 -x +C 11 + 1 11 + 4x…

A:

Q: L-1| 12 ] = ? (s-3)+ %3D

A: