Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do this by inspection, i.e. without much written computation.) 6 ([-] [3³])| 35 A. S₁ = span The dimension of S₁ is B. S₂ = span The dimension of S₂ is C. S3= span ([]][3][)) 0 -1 0 0 0 24 The dimension of S3 is

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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do
this by inspection, i.e. without much written computation.)
A. S₁ = span
The dimension of S₁ is
6
-21
([-]-[3³³])|
·10 35
B. S₂ = span
The dimension of S₂ is
C. S3= span
12
The dimension of S3 is
D. S4= span
3 3
·CH·H&HD
−1 3
0 0
The dimension of S4 is
E. S5 = span
CHED
-2
(
The dimension of S5 is
37])
-37
3
-3
3
24
-15
[[ ]]
15
2
-15
13
Transcribed Image Text:Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do this by inspection, i.e. without much written computation.) A. S₁ = span The dimension of S₁ is 6 -21 ([-]-[3³³])| ·10 35 B. S₂ = span The dimension of S₂ is C. S3= span 12 The dimension of S3 is D. S4= span 3 3 ·CH·H&HD −1 3 0 0 The dimension of S4 is E. S5 = span CHED -2 ( The dimension of S5 is 37]) -37 3 -3 3 24 -15 [[ ]] 15 2 -15 13
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