Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do this by inspection, i.e. without much written computation.) 6 ([-] [3³])| 35 A. S₁ = span The dimension of S₁ is B. S₂ = span The dimension of S₂ is C. S3= span ([]][3][)) 0 -1 0 0 0 24 The dimension of S3 is
Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do this by inspection, i.e. without much written computation.) 6 ([-] [3³])| 35 A. S₁ = span The dimension of S₁ is B. S₂ = span The dimension of S₂ is C. S3= span ([]][3][)) 0 -1 0 0 0 24 The dimension of S3 is
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do
this by inspection, i.e. without much written computation.)
A. S₁ = span
The dimension of S₁ is
6
-21
([-]-[3³³])|
·10 35
B. S₂ = span
The dimension of S₂ is
C. S3= span
12
The dimension of S3 is
D. S4= span
3 3
·CH·H&HD
−1 3
0 0
The dimension of S4 is
E. S5 = span
CHED
-2
(
The dimension of S5 is
37])
-37
3
-3
3
24
-15
[[ ]]
15
2
-15
13](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf673b33-84d3-4207-a3d8-77b439e8ab65%2Ffc88590c-a96f-4012-8603-c3075b22c6ce%2Fgh367k8_processed.png&w=3840&q=75)
Transcribed Image Text:Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do
this by inspection, i.e. without much written computation.)
A. S₁ = span
The dimension of S₁ is
6
-21
([-]-[3³³])|
·10 35
B. S₂ = span
The dimension of S₂ is
C. S3= span
12
The dimension of S3 is
D. S4= span
3 3
·CH·H&HD
−1 3
0 0
The dimension of S4 is
E. S5 = span
CHED
-2
(
The dimension of S5 is
37])
-37
3
-3
3
24
-15
[[ ]]
15
2
-15
13
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