Each plate of a parallel-plate capacator is a square withside length r, and the plates are separated by a distanced. The capacitor is connected to a source of voltage V Aplastic slab of thickness d and dielectric constant K isinserted slowly between the plates over the time periodAt until the slab is squarely between the plates. Whilethe slab is being inserted, a current runs through thebattery/capacitor circuit. (Figure 1)PartAssuExprperm► VieFigure1 of 1Sub Assuming that the dielectric is inserted at a constant rate, find the current I as the slab is inserted.Express your answer in terms of any or all of the given variables V, K,r, d, At, and eg,permittivity of free space.the

Given The dimensions of the plate is( r x r) Time taken is Δt Dielectric constant is K Distance…

Answered: Each plate of a parallel-plate…

Engineering

Electrical Engineering

Each plate of a parallel-plate capacator is a square with

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter21: Resistive-capacitive Series Circuits

Section: Chapter Questions

Problem 6RQ: A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating...

See similar textbooks

Related questions

Q: Sketch the Current through through cach Zenner diode 7v+ "Δ 1042 www 3v 5K2 Sve #2.5v

A: Zenor diode

Q: Intrinsic breakdown occurs in time of the order of

A: As per the guidelines, we supposed to answer one question at a time so please ask other questions…

Q: What is the I total

A: For the given series RLC circuit the value of total current needs to be calculated and the same can…

Q: 7). Defarmne the nde equations.. P4 VA VB Vc I3 Ii 善Pu Is

A: In this question we will write node equations..

Q: Draw the output voltage waveform for each circuit in Figure R www 2.2 ΚΩ +30 V Vin OV -30 V 8 D₁ D₂…

A: The problem has been solved as follows

Q: C1 =5 µF %3D C3 = 8 µF C2 = 4 µF C4 = 6 µF Cs = 4 µF DURACELL VT = 12 V Vhat is the voltage across…

Q: of 不 s;子 4V- Vo Det ve for (4) C-) agele V.

A: Clamper circuit contains diode, capacitor and resistor. Output of the clamper depends on the…

Q: What is the value of I? A) 0.1 A B) IA C) -1A 1A(1 70 IA D) -2 A E) 0 A

A: Given circuit,

Q: 1 Rsc 4Cfclk Bilinear

A: Capacitor: This is an energy storing device and it stores the energy in the electric field. Its unit…

Q: Determine if the LED will blew up if the maximum current will flow on it assuming the maximum rating…

A: DC analysis of transistor is done by finding the finding the DC biasing values also known as Q…

Q: VII. Please answer the fol lowing questions according to the following circuit: 1. Assume Qa and Qu…

Concept explainers

Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.

Question

Each plate of a parallel-plate capacator is a square with
side length r, and the plates are separated by a distance
d. The capacitor is connected to a source of voltage V A
plastic slab of thickness d and dielectric constant K is
inserted slowly between the plates over the time period
At until the slab is squarely between the plates. While
the slab is being inserted, a current runs through the
battery/capacitor circuit. (Figure 1)
Part
Assu
Expr
perm
► Vie
Figure
1 of 1
Sub

Assuming that the dielectric is inserted at a constant rate, find the current I as the slab is inserted.
Express your answer in terms of any or all of the given variables V, K,r, d, At, and eg,
permittivity of free space.
the

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.
A pure capacitive circuit is connected to a 480-volt, 60-Hz power source. An ammeter indicates a current flow of 24 amperes. The circuit current must be reduced to 16 amperes by connecting a second capacitor in series with the first. What is the value of the existing capacitor? What value capacitor should be connected in series with the original capacitor to limit the circuit current to 16 amperes?
In a pure capacitive circuit, does the current lead or lag the voltage?
A postage stamp mica capacitor has the following color marks starting at the upper left dot: yellow, violet, brown, green, no color, and blue. What are the capacitance value, tolerance, and voltage rating of this capacitor?
A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted between the plates without changing the spacing, and the capacitance becomes 15 F. What is the dielectric constant of this material?
MAKE ONE ORIGINAL WORDED PROBLEM WITH DIAGRAM AND ITS FREE BODY DIAGRAM FOR CAPACITANCE IN SERIES CONNECTION NO UPVOTE IF NOT ORIGINAL AND NO DIAGRAMS ONLY UPVOTE IF FOLLOWED INSTRUCTIONS SHOW COMPLETE SOLUTIONS
For circuit given in figure 5, find total capacitance and total charge. C1 = 20pF C2 = 30pF 5V C3 = 30pF C5 10pF C4 = 30pF Figure 5
(c) The capacitors are connected as shown in Figure 3 and charged by a 100 V battery. Find: The equivalent capacitance of the circuit ii. The total charge ii. The voltage drop across C3 iv. The charge on C1 C2 C3 2.00uF C1 6.00uF Vs 1µF 100v C4 4.00uF Figure 3
In a given parallel plate capacitor with a stored energy of " W" Joules, if the capacitance value is increased by 11 times and applied voltage is increased by 3 times then the new value of the stored energy =. Joules. O 20*W O 99*W O 198*W O 50*W
1. A purely resistive circuit the current is leading by 90° with respect to voltage. 2. A purely inductive circuit the current is lag behind the voltage by 90°. 3. A purely capacitive circuit the current is lead by 90° with respect to the voltage. 4. A capacitor element stored magnetic energy. 5. An inductor element stored electrical energy. 6. Resistor elements consume power. 7. Angle between current and voltage is called power. 8. The power factor angle for a purely resistive is zero. 9. The power factor angle for a purely inductive load is -90°. 10. The power factor of a purely capacitive is leading.
(c) The capacitors are connected as shown in Figure 3 and charged by a 100 V battery. Find: i. The equivalent capacitance of the circuit ii. The total charge i. The voltage drop across C3 iv. The charge on C, 2.00uF C1 6.00uF HH Vs 1UF 100v C4 4.00uF Figure 3
C3 Vin \aov AC Cr D3 Vin Voat /calculate Vout and explain the followingcircait. ALl capacitor 0,4MF And Calculate the energy trapped in each capacitor and the total energy trapped in the circuit ell