Each of the two systems is released from rest. Calculate the speed v of each 62-lb cylinder after the 48-lb cylinder has dropped 5.6 ft. The 26-lb cylinder of case (a) is replaced by a 26-lb force in case (b). 48 48 62 62 lb lb lb lb 26 lb 26 lb (a) Answers: (a) v = i (b) ft/sec

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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**Problem Description:**

Each of the two systems is released from rest. Calculate the speed \( v \) of each 62-lb cylinder after the 48-lb cylinder has dropped 5.6 ft. The 26-lb cylinder of case (a) is replaced by a 26-lb force in case (b).

**Diagrams:**

There are two diagrams labeled (a) and (b).

1. In diagram (a):
   - A pulley system is depicted with three cylinders.
   - The first cylinder is labeled 48 lb.
   - The second cylinder is labeled 62 lb.
   - The third cylinder is labeled 26 lb.

2. In diagram (b):
   - The same pulley system is depicted, but the third 26-lb cylinder is replaced with a 26-lb force moving downward.

**Questions:**

Calculate the speed \( v \) of the 62-lb cylinder after the 48-lb cylinder has dropped 5.6 ft for both cases (a) and (b).

**Answers:**

For case (a):
\[ v = \quad \text{ft/sec} \]

For case (b):
\[ v = \quad \text{ft/sec} \]
Transcribed Image Text:**Problem Description:** Each of the two systems is released from rest. Calculate the speed \( v \) of each 62-lb cylinder after the 48-lb cylinder has dropped 5.6 ft. The 26-lb cylinder of case (a) is replaced by a 26-lb force in case (b). **Diagrams:** There are two diagrams labeled (a) and (b). 1. In diagram (a): - A pulley system is depicted with three cylinders. - The first cylinder is labeled 48 lb. - The second cylinder is labeled 62 lb. - The third cylinder is labeled 26 lb. 2. In diagram (b): - The same pulley system is depicted, but the third 26-lb cylinder is replaced with a 26-lb force moving downward. **Questions:** Calculate the speed \( v \) of the 62-lb cylinder after the 48-lb cylinder has dropped 5.6 ft for both cases (a) and (b). **Answers:** For case (a): \[ v = \quad \text{ft/sec} \] For case (b): \[ v = \quad \text{ft/sec} \]
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