each of the tests, what would be the conclusion if the test were carried out using the α = 0.05 level of significance? H0 : µ = 120, H1:µ ≠ 120, n = 36, S.D of population= 10.3, sample mean = 117.0 Should the null
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For each of the tests, what would be the conclusion if the test were carried out using the α = 0.05 level of significance?
H0 : µ = 120, H1:µ ≠ 120, n = 36, S.D of population= 10.3, sample
Should the null be rejected?
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- The manufacturer claims that your new car gets 35 mpg on the highway. You suspect that the mpg is a different number for your car. The 66 trips on the highway that you took averaged 40.4 mpg and the standard deviation for these 66 trips was 13.7 mpg. What can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest that the sample mean is not significantly different from 35 at αα = 0.01, so there is statistically insignificant evidence to conclude that the sample mean mpg for your car on the highway is different from 40.4. The data suggest that the populaton mean is significantly different from…The manufacturer claims that your new car gets 31 mpg on the highway. You suspect that the mpg is less for your car. The 57 trips on the highway that you took averaged 28.8 mpg and the standard deviation for these 57 trips was 10.7 mpg. What can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest that the populaton mean is significantly less than 31 at αα = 0.01, so there is statistically significant evidence to conclude that the population mean mpg for your car on the highway is less than 31. The data suggest that the population mean is not significantly less than 31 at αα = 0.01, so there…The manufacturer claims that your new car gets 26 mpg on the highway. You suspect that the mpg is more for your car. The 48 trips on the highway that you took averaged 30.4 mpg and the standard deviation for these 48 trips was 9.4 mpg. What can be concluded at the αα = 0.10 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis.
- The mean number of eggs per person eaten in the United States is 253. Do college students eat less eggs than the average American? The 69 college students surveyed averaged 230 eggs per person and their standard deviation was 78.3. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer ≠ > < = H1:H1: ? μ p Select an answer > < ≠ = The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean is not significantly less than 253 at αα = 0.01, so there is statistically insignificant…Only about 17% of all people can wiggle their ears. Is this percent different for millionaires? Of the 356 millionaires surveyed, 78 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? The test statistic= (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.)A sample of 35 observations is selected from a normal population. The sample mean is 29, and the population standard deviation is 2. Conduct the following test of hypothesis using the 0.02 significance level. H0: μ ≤ 28 H1: μ > 28 a. What is the decision rule? b. What is your decision regarding H0? c. What is the p-value?
- For the question attached in the photos: Given the null and alternative hypothesis for the test & locate the rejection for the test using a 5% significance level Find the standard error of the meanA test of sobriety involves measuring the subject's motor skills. Twenty randomly-selected sober subjects take the test and produce a mean score of 41.0 with a standard deviation of 3.7. At the 0.01 level of significance, test the claim that the true mean score for all sober subjects is equal to 35.0. Use the traditional method of testing hypotheses. The results for the test turn out to be: Ho: H = 35.0. H1:µ/35.0. Test statistic: t 7.252. Critical values: t = -2.861, 2.861. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the mean is equal to 35.0. If a defense attorney argues the results are not valid because the sample size was too small, is his argument valid here? Yes, because the t-test is not as powerful as the z-test. No, because we rejected the null hypothesis. Yes, because we rejected the null hypothesis. O No, the sample size is never an issuc. O We need more information to answer.Management at Deluxe Diner is in process of establishing a quality control system for the time it takes to initially make contact with a table of patrons. A sample of size 3 is taken on each of the five different days. Suppose you calculated = 100 and R = 40. What is the 3-sigma UCL for the X-bar chart?
- Say we were testing the effects of taking calcium on bone density levels and obtained a positive and significant value for our independent t test result. What would you write (using APA format) when performing a percentage of variance explained test on the data and received a value of r2=.38.Suppose you are conducting a test of significance for the weight of a bag of Lay's Potato Chips. Your hypotheses are: Null: The population mean weight is 10 ounces. Alternative: The population mean weight is less than 10 ounces. From your random sample of 40 bags of chips, you conclude that the mean weight of all bags of Lay's chips is less than 10 ounces with a p-value of 0.017. Which of the following statements best describes what that p-value means? (A) The probability that the mean weight of all bags of Lay's chips is 10 ounces is 0.017. (B) If the mean weight of all bags of Lay's chips is 10 ounces, the probability that a random sample of 40 bags would have a mean as low or lower than the one found is 0.017. (C) If the mean weight of all bags of Lay's chips is less than 10 ounces, the probability that a random sample of 40 bags would have a mean as low or lower than the one found is 0.017. (D) The probability that the mean weight of all bags of Lay's chips is less than 10…When 40 people used the Weight Watchers dies for one year, their mean weight loss was 3.0 lb and the standard deviation was 4.9 lb. Use a 0.01 significance level to test the claim that the mean weight loss is greater than 0. (Show the solution) A. The null hypothesis is i. The mean weight loss is equal to 0. ii. The mean weight loss is not equal to 0. iii. The mean weight loss is greater than 0. iv. The mean weight loss is less than 0. B. The computed t-test statistic is i. 4.468 ii. 4.977 iii. 3.872 iv. 3.391 C. The critical/tabular t-test statistic is i. 2.426 ii. 1.684 iii. 1.685 iv. 2.423 D. Decision rule: i. Do not reject the null hypothesis. ii. Reject the null hypothesis. E. The final conclusion is i. The mean weight loss is not equal to 0 therefore Weight Watchers is effective. ii. The mean weight loss is less than 0 therefore Weight Watchers is not effective. iii. The mean weight loss is equal to 0 therefore Weight Watchers…
