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Each of the solutions shown uses a different property of exponents. Match each property to the solution that uses it. 8 (16×25)² 1 - 3 x 8 1 - -|N 3 1 2 = 16 x 25 = 4 x 5 = 20 = 8 = 8 = 4 1 1 + - 3 NI → W|N 2 3 -|N 1 27 27 6 (63) ⁰ 2/3 1 = 27 - 13 = 3 1 = 273 1 = 9 = 9² = 81 2 1 3 x6 3

Each of the solutions shown uses a different property of exponents. Match each property to the solution that uses it. 8 (16×25)² 1 - 3 x 8 1 - -|N 3 1 2 = 16 x 25 = 4 x 5 = 20 = 8 = 8 = 4 1 1 + - 3 NI → W|N 2 3 -|N 1 27 27 6 (63) ⁰ 2/3 1 = 27 - 13 = 3 1 = 273 1 = 9 = 9² = 81 2 1 3 x6 3

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Which equation is power of a power,power of product,product of powers,quotient of powers?

Each of the solutions shown uses a different property of exponents. Match each property to the solution that uses it. 1 2 (16 × 25) 2 = 16 = 16² x 25 = 4 × 5 1 - اس 1 8 x83 = 20 - 13 -13 ~/3 = 8 2 =83 = 4 + -|N 1 2 و) 27 27 1) 6 (3) . ~/3 2 1 = 27 3 = 3 - 13 = 273 1 = 9 = 92 = 81 ×6 2 1 3 - 13 - - 13
Transcribed Image Text:Each of the solutions shown uses a different property of exponents. Match each property to the solution that uses it. 1 2 (16 × 25) 2 = 16 = 16² x 25 = 4 × 5 1 - اس 1 8 x83 = 20 - 13 -13 ~/3 = 8 2 =83 = 4 + -|N 1 2 و) 27 27 1) 6 (3) . ~/3 2 1 = 27 3 = 3 - 13 = 273 1 = 9 = 92 = 81 ×6 2 1 3 - 13 - - 13
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