Each of the solutions shown uses a different property of exponents. Match each property to the solution that uses it. 8 (16×25)² 1 - 3 x 8 1 - -|N 3 1 2 = 16 x 25 = 4 x 5 = 20 = 8 = 8 = 4 1 1 + - 3 NI → W|N 2 3 -|N 1 27 27 6 (63) ⁰ 2/3 1 = 27 - 13 = 3 1 = 273 1 = 9 = 9² = 81 2 1 3 x6 3
Each of the solutions shown uses a different property of exponents. Match each property to the solution that uses it. 8 (16×25)² 1 - 3 x 8 1 - -|N 3 1 2 = 16 x 25 = 4 x 5 = 20 = 8 = 8 = 4 1 1 + - 3 NI → W|N 2 3 -|N 1 27 27 6 (63) ⁰ 2/3 1 = 27 - 13 = 3 1 = 273 1 = 9 = 9² = 81 2 1 3 x6 3
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
Which equation is power of a power,power of product,product of powers,quotient of powers?
![Each of the solutions shown uses a different property of
exponents. Match each property to the solution that uses it.
1
2
(16 × 25) 2 = 16
= 16² x 25
= 4 × 5
1
- اس
1
8 x83
=
20
- 13
-13 ~/3
= 8
2
=83
= 4
+
-|N
1
2
و)
27
27
1) 6
(3) .
~/3
2
1 = 27
3
= 3
- 13
= 273
1
= 9
= 92
= 81
×6
2 1
3
- 13
-
- 13](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed3eeee6-4e49-429a-ae54-1472e7ff4680%2F4e5ad66e-4e6e-464b-b9f3-f854e4c0e9d3%2Fmlp0ylj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Each of the solutions shown uses a different property of
exponents. Match each property to the solution that uses it.
1
2
(16 × 25) 2 = 16
= 16² x 25
= 4 × 5
1
- اس
1
8 x83
=
20
- 13
-13 ~/3
= 8
2
=83
= 4
+
-|N
1
2
و)
27
27
1) 6
(3) .
~/3
2
1 = 27
3
= 3
- 13
= 273
1
= 9
= 92
= 81
×6
2 1
3
- 13
-
- 13
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