Each of the eight conductors in the figure carries 3.41 A of current into or out of the page. Two paths are indicated for the line integral fi B. ds. What is the value of the integral for (a) path 1 and (b) path 2?
Each of the eight conductors in the figure carries 3.41 A of current into or out of the page. Two paths are indicated for the line integral fi B. ds. What is the value of the integral for (a) path 1 and (b) path 2?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Description of Problem:**
Each of the eight conductors in the figure carries a current of 3.41 A either into or out of the page. There are two paths labeled for evaluating the line integral \(\oint \vec{B} \cdot d\vec{s}\). What is the value of the integral for:
(a) Path 1
(b) Path 2
**Diagrams and Analysis:**
- **Diagram Explanation:**
The image shows two closed paths labeled 1 and 2, encompassing some of the conductors. Each conductor is represented with a circle, and the direction of current is indicated by a dot for outward current and a cross for inward current.
- **Path 1:**
Encloses three conductors, two with crosses (inward current) and one with a dot (outward current).
- **Path 2:**
Encloses three conductors, two with crosses (inward current) and one with a dot (outward current), similar to Path 1.
**Calculations:**
- **(a) Path 1:**
The value of the line integral for Path 1 is calculated as 2.51.
- **(b) Path 2:**
The value of the line integral for Path 2 is calculated as 0.
**Input and Results:**
- **(a) Number:**
2.51 Units: (Selectable dropdown for units, not specified)
- **(b) Number:**
0 Units: T· (Presumably Tesla, for the magnetic field)
These calculations likely derive from applying Ampère's Law, which relates the integral of the magnetic field around a closed loop to the current enclosed by that loop.
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