Each of four particles move along an x axis. Their coordinates (in meters) as functions of time (in seconds) are given by particle 1: x(t) = 3.5 – 2.7t^3 particle 2: x(t) = 3.5 + 2.7t^3 particle 3: x(t) = 3.5 + 2.7t^2 particle 4: x(t) = 3.5 – 3.4t – 2.7t^2 Which of these particles have constant acceleration? A) All four B) Only 1 and 2 C) Only 1 and 3 D) Only 3 and 4

Each of four particles move along an x axis. Their coordinates (in meters) as functions of time (in seconds) are given by particle 1: x(t) = 3.5 – 2.7t^3 particle 2: x(t) = 3.5 + 2.7t^3 particle 3: x(t) = 3.5 + 2.7t^2 particle 4: x(t) = 3.5 – 3.4t – 2.7t^2 Which of these particles have constant acceleration? A) All four B) Only 1 and 2 C) Only 1 and 3 D) Only 3 and 4

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter3: Vectors And Two-Dimensional Motion

Section: Chapter Questions

Problem 3WUE: Find (a) the x- and (b) y-components of R = 2A B if A has components Ax = 15.0 m and Ay = 12.0 m...

See similar textbooks

Similar questions

Find (a) the x- and (b) y-components of R = 2A B if A has components Ax = 15.0 m and Ay = 12.0 m whereas B has components Bx = 24.0 m and By = 8.00 m. (See Section 3.2.)
A child starts at one corner of a cubical jungle gym in a playground and climbs up to the diagonally opposite corner. The original corner is the coordinate origin, and the x, y and z axes are oriented along the jungle gym edges. The length of each side is 2 m. The child's displacement is: 2î + 2j + 3.5k 2î+ 2f + 2.8k O 2î + 2j + 2k O 3.5i+ 3.5j+ 3.5k 2.81 + 2.8j + 2k
The position of a particle in space at time tis: r(t) = (sec(t)) * i + (tan t) * j + 4/3 tk. Write the particle's velocity at time t = (pi / 6) as the product of its speed and direction.
Note: Please provide a simple and step-by-step solution.
Problem 4: Two points in a plane have polar coordinates P1(2.4 m, Jt/6) and P2(3.8 m, 2jt/3). P1(, y) m 20% Part (a) Determine the x value of the Cartesian coordinates for Pj.
Refer to the information in Double Play Displacement to answer this question. The magnitude of the resultant displacement is A, 60 m B, 7.7 m c, 1.8 × 103 m d, 42 m
The velocity of a particle as a function of time is given by v(t)=(3t-t )i-4 j all in S.I. units. a) What are the dimensions of the "-1 " in the – ti term? What are the units of the "3 " in the 3t i term? b) Find the position vector of the particle, r(t), if r(0) = -5 i- 2j :) Find the time ti > 0 when the position in the i direction is a maximum. d) Find a 1 -> 3 the average acceleration vector in the time interval 1 to 3 seconds.
The equation r(t) = ( sin t)i + ( cos t)j + (t) k is the position of a particle in space at time t. Find the particle's velocity and acceleration vectors. π Then write the particle's velocity at t= as a product of its speed and direction. The velocity vector is v(t) = (i+j+ k.
Given two vectors: The expression 2N - M is: (A) No Answer B C D E -7i+ 12j - 3k - 12i- 36j+ 10k -j+ 6k - i+7k M = −3î + 6ĵ - 5k and № = -2î +3ĵ+ k
Each of four particles moves along an x axis. Their coordinates (in meters) as functions of time (in seconds) are given by particle 1: x(t) = 3.5 - 2.7t3 particle 2: x(t) = 3.5 + 2.7t3 particle 3: x(t) = 3.5 + 2.7t2 particle 4: x(t) = 3.5 - 3.4t - 2.7t2 For which of these particles is the velocity increasing for t> 0? A Only 1 (B) Only 2, 3, and 4 All four D Only 2 and 3 At a stop light, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity and the car accelerates at 3 m/s². How much time does the car take to catch up to the truck? A) 15 s B) 10 s 25 s D) 5 s
An ion's position vector is initially r==(5i-6j+2k)m, and 10 s later it is r=(-2i+8j-2k)m.In unit-vector notation ,what is its Vavg during the 10s?
For the following displacement vectors in meters: A = +4.0 - 5.0k, B=-3.0 +2.0k, and C= -3.0-2.0 +1.0k. Calculate (a) A −2B +3C, (b) A-B, (c) the angle between A and B, and (d) A × (B+C).