Each experiment compares three treatment conditions, and each experiment uses separate samples of n = 10 for eachtreatment.Experiment A Treatment2M = 2s = 12Experiment B Treatment123M = 1M = 10M = 20S = 2s = 1S = 2Just looking at the data - without doing any calculations, which MS between is larger?O a) Experiment AOb) Experiment BOc) They are the samed) Cannot determine1M = 1s = 103M = 3s = 15

Given data Experiment A treatment 1 2 3 M=1 M=2 M=3 s=10…

Answered: Each experiment compares three…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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oli.cmu.edu/course/a2/rest/assessement/deliver?attempt=1&context=7e118d530a0001dc243d5eafc726f6eb Countdown: Days:-0 Time:-12:02:41 10 points Researchers created a new fertilizer. They conducted an experiment to compare the new fertilizer to the old fertilizer. They divided tomato plants into two groups. They applied the new fertilizer to one group and the old fertilizer to another group. The variable is the number of tomatoes per plant on a randomly selected day. 0 0 Old Fertilizer N=65 2 4 New Fertilizer N=58 4 6 6 20 600 8 8 10 10 12 14 16 12 14 Number of tomatoes per plant 18 16 18 20 20 Select one answer. Which one of the following statements is valid? A. O The new formula of fertilizer works better. Plants with the new fertilizer had more tomatoes. B. O The old formula of fertilizer was better because the plant with the most tomatoes was treated with the old fertilizer. The average number of tomatoes per plant with the old fertilizer is higher than the average amount of tomatoes…
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
Experiment 3: Fifteen female CSCC students and 10 male CSCC students are randomly selected to determine if the mean time studying for females is significantly more than the mean study time for males. It can be assumed that all study times are normally distributed. Are these samples independent or dependent? Find the null and alternative hypothesis. H0: Ha:
A paired and independent- sample t-test each had degrees of preedom (df)=33.What are the sample sizes? A.paired-samples t-test 34/independnt-samples t-test 35 B.paired-samples t-test 32/independent-samples t-test 31 C.paired-smaples t-test 35/independent- samples t-test 34
2. Five 2 cm thick experimental pieces of an insulation material were tested atrandom. Resulted compression (y) was measured recorded for the given amount ofmeasured pressure. The data are listed below:Pressure Compression1 12 23 24 35 5Fit a simple linear model relating compression y to the applied pressure x and find:a) error variance.b) the coefficient of correlation.
1
A two-way ANOVA experiment with no interaction is conducted. Factor A has four levels (columns) and Factor B has eight levels (rows). Assume normality in the underlying populations. The results include the following sum of squares terms: SST=367.5 SSA = 207.0 SSE = 52.4 a. Construct an ANOVA table. (Round "SS" and "MS" to 2 decimal places and "F" to 3 decimal places.) ANOVA Source of Variation Rows Columns Error Total SS X Answer is complete but not entirely correct. 207.00 X 108.10 X 52.40 367.50 df 7 3 21 31 MS 29.57 X 36.03 X 2.50 F 11.850 X 14.412 X p- value 0.001 0.000
Phosphorous is a chemical that is found in many household cleaning products. Unfortunately, phosphorous also finds its way into surface water, where it can harm fish, plants, and other wildlife. Two methods of phosphorous reduction are being studied. At a random sample of 7 locations, both methods were used and the total phosphorous reduction (mg/L) was recorded. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value a small amount and thereby produce a slightly more "conservative" answer. Site 1 2 3 4 5 6 7 Method I: 0.013 0.020 0.015 0.055 0.007 0.002 0.010 Method II: 0.014 0.045 0.017 0.039 0.017 0.001 0.013 Do these data indicate a difference (either way) in the average reduction of phosphorous between the two methods? Use α = 0.05. (Let d = Method I − Method II.) (i) What is the level of significance? What is the value of the sample test statistic? (Round…
part F G
A two-way ANOVA experiment with interaction was conducted. Factor A had three levels (columns), factor B had five levels (rows), and six observations were obtained for each combination. Assume normality in the underlying populations. The results include the following sum of squares terms: SST=1542 SSA= 1042 SSB = 358 SSAB = 39 a. Construct an ANOVA table. (Round "MS" to 4 decimal places and "F" to 3 decimal places.) ANOVA Source of Variation Rows Columns Interaction Error Total SS 0 df Answer is not complete. 0 MS F p- value 0.000 0.000 0.002
2. A researcher had rats engage in a lever-press task for either a small, medium, or larger reward. The number of lever presses was the dependent variable. The data were as follows: Reward Size Small Medium Large 1 4 6 4 3 5 1 4 4 2 5 T = 13 SS = 2.75 T= 6 T= 20 SS = 9 SS = 2 EX2 = 165 a. Do the data indicate that reward size had a significant impact on lever-pressing? Use the hypothesis testing steps & p = .05. Compute any necessary post-hoc tests. b. Compute eta-squared to measure the effect size.
2. Use the values in the matrix to solve the equations given: a. P(A∪D) =b. P(E∪ B) =c. P(D∪ E) =d. P(C∪ F) =

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