Each exam question posted to the study website Begg.com has a probability 0.6 of being answered correctly. However, for each question posted there is a probability 0.5 of being caught by the university authorities. What is the probability that a student who posts two questions receives at least one right answer and does not get caught on either question? You may assume that the events involved are mutually independent.I have tried but confused really on what method to use, idk if there is a formula for stuff like thisI have tried 1-(0.4x0.5)2 which is 1 minus P(no answer x caught) twice but i got 0.96 which i think is wrong

Each exam question posted to the study website Begg.com has a probability 0.6 of being answered correctly. However, for each question posted there is a probability 0.5 of being caught by the university authorities. What is the probability that a student who posts two questions receives at least one right answer and does not get caught on either question? You may assume that the events involved are mutually independent.I have tried but confused really on what method to use, idk if there is a formula for stuff like thisI have tried 1-(0.4x0.5)2 which is 1 minus P(no answer x caught) twice but i got 0.96 which i think is wrong

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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