Each exam question posted to the study website Begg.com has a probability 0.6 of being answered correctly. However, for each question posted there is a probability 0.5 of being caught by the university authorities. What is the probability that a student who posts two questions receives at least one right answer and does not get caught on either question? You may assume that the events involved are mutually independent. I have tried but confused really on what method to use, idk if there is a formula for stuff like this I have tried 1-(0.4x0.5)2 which is 1 minus P(no answer x caught) twice but i got 0.96 which i think is wrong

Each exam question posted to the study website Begg.com has a probability 0.6 of being answered correctly. However, for each question posted there is a probability 0.5 of being caught by the university authorities. What is the probability that a student who posts two questions receives at least one right answer and does not get caught on either question? You may assume that the events involved are mutually independent. I have tried but confused really on what method to use, idk if there is a formula for stuff like this I have tried 1-(0.4x0.5)2 which is 1 minus P(no answer x caught) twice but i got 0.96 which i think is wrong

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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