each distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.3 cm. ability that an individual distance is greater than 214.30 cm. ability that the mean for 15 randomly selected distances is greater than 203.50 cm. normal distribution be used in part (b), even though the sample size does not exceed 30? ty is decimal places as needed) ty is . decimal places as needed.) correct answer below. ww mal distribution can be used because the mean is large. mal distribution can be used because the original population has a normal distribution. mal distribution can be used because the finite population correction factor is small. mal distribution can be used because the probability is less than 0.5

each distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.3 cm. ability that an individual distance is greater than 214.30 cm. ability that the mean for 15 randomly selected distances is greater than 203.50 cm. normal distribution be used in part (b), even though the sample size does not exceed 30? ty is decimal places as needed) ty is . decimal places as needed.) correct answer below. ww mal distribution can be used because the mean is large. mal distribution can be used because the original population has a normal distribution. mal distribution can be used because the finite population correction factor is small. mal distribution can be used because the probability is less than 0.5

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
Next Question Assume that a randomly selected subject is given a bone density test. Those test s Draw a graph and find the probability of a bone density test score between - 2.15 and 2.15. distributed with a mean of 0 and a standard deviation of 1. ..... Sketch the region. Choose the correct graph below. A. В. С. D. -2.15 2.15 -2.15 2.15 -2.15 2.15 -2.15 2.15 The probability is (Round to four decimal places as needed.)
I need help with parts b,c, and d please B is not 992
Bootstrapping is a helpful tool when A. the sample size is too small to get an accurate estimate B. the sample proportion is very close to 0 or 1 C. we want to estimate a standard deviation in any context D. we don't have technology nearby
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Can someone please help? Thank you.
Next question The overhead reach distances of adult females are normally distributed with a mean of 202.5 cm and a standard deviation of 8.6 cm. a. Find the probability that an individual distance is greater than 212.50 cm. b. Find the probability that the mean for 20 randomly selected distances is greater than 200.30 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? a. The probability is (Round to four decimal places as needed.) b. The probability is (Round to four decimal places as needed.) c. Choose the correct answer below. OA. The normal distribution can be used because the probability is less than 0.5 OB. The normal distribution can be used because the mean is large. OC. The normal distribution can be used because the finite population correction factor is small. O D. The normal distribution can be used because the original population has a normal distribution. H a Type here esc ? 12 a * # 3 101 $ 4 ts % 5 X 16 40 a # hp &…
Save In a study on infants, one of the characteristics measured was head circumference. The mean head circumference of 9 infants was 34.9 centimeters (cm). Complete parts (a) through (d) below. Click here to view Page 1 of the table of areas under the standard normal curve. Click here to view Page 2 of the table of areas under the standard normal curve. a. Assuming that head circumferences for infants are normally distributed with standard deviation 2.4 cm, determine a 95% confidence interval for the mean head circumference of all infants. The confidence interval for the mean head circumference of all infants is from cm to decimal place as needed.) cm. (Round to one
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