each distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.3 cm. ability that an individual distance is greater than 214.30 cm. ability that the mean for 15 randomly selected distances is greater than 203.50 cm. normal distribution be used in part (b), even though the sample size does not exceed 30? ty is decimal places as needed) ty is . decimal places as needed.) correct answer below. ww mal distribution can be used because the mean is large. mal distribution can be used because the original population has a normal distribution. mal distribution can be used because the finite population correction factor is small. mal distribution can be used because the probability is less than 0.5
each distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.3 cm. ability that an individual distance is greater than 214.30 cm. ability that the mean for 15 randomly selected distances is greater than 203.50 cm. normal distribution be used in part (b), even though the sample size does not exceed 30? ty is decimal places as needed) ty is . decimal places as needed.) correct answer below. ww mal distribution can be used because the mean is large. mal distribution can be used because the original population has a normal distribution. mal distribution can be used because the finite population correction factor is small. mal distribution can be used because the probability is less than 0.5
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Step 1
Mean= 205
Standard deviation = 8.3
Z-score = (x-mean)/standard deviation
P(X>214.3) = ?
P(x>203.5)=?
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