Each box shown below has mass equal, m. In each case the box moves along a frictionless surface. By Newton's 2nd Law,, a = F/m. Rank order the figures from least to the greatest acceleration. (Hint: Determine the net component of force for each.) Note: cos 30° = cos 60° = F2 = 80√√2 N 60° 30° m 60° A F₂ = 420 N F₁ = 80 N F,= 200 N F₁ = 40√√2 N F3 = 400 N 60° 30° F₁ =550 N 3 m F2 = 500 N F2 = 10√2 N 30° F₁ = 20 N 60° E F₁ = 200 N m D F₁ = 600 N m F₁ = 680 N E Place the Rank Order of the acceleration of the box from least to greatest in the spaces below: EB A Least DF FC L Greatest
Each box shown below has mass equal, m. In each case the box moves along a frictionless surface. By Newton's 2nd Law,, a = F/m. Rank order the figures from least to the greatest acceleration. (Hint: Determine the net component of force for each.) Note: cos 30° = cos 60° = F2 = 80√√2 N 60° 30° m 60° A F₂ = 420 N F₁ = 80 N F,= 200 N F₁ = 40√√2 N F3 = 400 N 60° 30° F₁ =550 N 3 m F2 = 500 N F2 = 10√2 N 30° F₁ = 20 N 60° E F₁ = 200 N m D F₁ = 600 N m F₁ = 680 N E Place the Rank Order of the acceleration of the box from least to greatest in the spaces below: EB A Least DF FC L Greatest
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Transcribed Image Text:Each box shown below has mass equal, m. In each case the box moves along a frictionless
surface. By Newton's 2nd Law,, a = F/m. Rank order the figures from least to the greatest
acceleration. (Hint: Determine the net component of force for each.)
Note: cos 30° =
cos 60°
=
F2 = 80√√2 N
60°
30°
m
60°
A
F₂ = 420 N
F₁ = 80 N
F,= 200 N
F₁ = 40√√2 N
F3 = 400 N
60°
30°
F₁ =550 N
3
m
F2 = 500 N
F2 = 10√2 N
30°
F₁ = 20 N
60°
E
F₁ = 200 N
m
D
F₁ = 600 N
m
F₁ = 680 N
E
Place the Rank Order of the acceleration of the box from least to greatest in the spaces below:
EB
A
Least
DF
FC
L
Greatest
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