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E6.16 Find vc(t) for t> 0 in Fig. E6.16. 0.25 H 1Ω the dif 12 V ib FIGURE 620-SLC circu Answer: s that describe ile boying noizvo(t) = -2e-2t cost insbla IS.d.git ni awore ai noitonut boq-1.5e-21 sin t + 24 V. O tol + R₁i(t) +v(t)=0 vc(t) + FIGURE E6.16 0.8 F Substit=0 second equation into the first yields du(t) v(1) R₂ + the circuitorame 24 V +tial conditions are 5Ω R₁ (²² + (x ² C + ²+ ) do + R₁ + R/ R₂LC S.T (0) = 18.0 4,(0) = 140 Foo so

E6.16 Find vc(t) for t> 0 in Fig. E6.16. 0.25 H 1Ω the dif 12 V ib FIGURE 620-SLC circu Answer: s that describe ile boying noizvo(t) = -2e-2t cost insbla IS.d.git ni awore ai noitonut boq-1.5e-21 sin t + 24 V. O tol + R₁i(t) +v(t)=0 vc(t) + FIGURE E6.16 0.8 F Substit=0 second equation into the first yields du(t) v(1) R₂ + the circuitorame 24 V +tial conditions are 5Ω R₁ (²² + (x ² C + ²+ ) do + R₁ + R/ R₂LC S.T (0) = 18.0 4,(0) = 140 Foo so

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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E6.16 Find vc(t) for t> 0 in Fig. E6.16. 0.25 H 1Ω ubst t = 0 the circuitran he dif 12 v (+ 5.02 FIGURE E6.16 vc(t) + Ht 0.8 F FIGURE 620-S&LC circu Answer: that describe 11216? in noid(t) = -2e-²t cost IS.d.git ni awode ei noitonut boq-1.5e-2t sin t + 24 V. O tole +R₁i(t) +v(t) = 0 (V) (1) (2) 1 ib 0.8 du(t) dt 24 V+tial conditions are c=1F R₂ tion into the first yields (² + (-1² + ²)) du + R₁ + R/0=0=01 -80 (0) = 13.0 (0)=140 Foo -so-
Transcribed Image Text:E6.16 Find vc(t) for t> 0 in Fig. E6.16. 0.25 H 1Ω ubst t = 0 the circuitran he dif 12 v (+ 5.02 FIGURE E6.16 vc(t) + Ht 0.8 F FIGURE 620-S&LC circu Answer: that describe 11216? in noid(t) = -2e-²t cost IS.d.git ni awode ei noitonut boq-1.5e-2t sin t + 24 V. O tole +R₁i(t) +v(t) = 0 (V) (1) (2) 1 ib 0.8 du(t) dt 24 V+tial conditions are c=1F R₂ tion into the first yields (² + (-1² + ²)) du + R₁ + R/0=0=01 -80 (0) = 13.0 (0)=140 Foo -so-
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