e2n cn U8n-5 %3D an-1(c – e)"(a – c)n' fan an bn-1(d – f)"(b – d)n' U8n-4 cn+1e2n U8n-3 = a"(a – c)"(c – e)n dn+1 f2n b* (b – d)"(d – f)r' e2n+1cn U8n-2 U8n-1 = а" (а — с)" (с — е)»' f2n+1dn br (b – d)"(d – f)n’ cn+1e2n+1 - u8n | U8n+1
e2n cn U8n-5 %3D an-1(c – e)"(a – c)n' fan an bn-1(d – f)"(b – d)n' U8n-4 cn+1e2n U8n-3 = a"(a – c)"(c – e)n dn+1 f2n b* (b – d)"(d – f)r' e2n+1cn U8n-2 U8n-1 = а" (а — с)" (с — е)»' f2n+1dn br (b – d)"(d – f)n’ cn+1e2n+1 - u8n | U8n+1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Solve the determine blue in the same way of the determine green

Transcribed Image Text:U8n-6 U8n-10
U8n-4
U8n-6 + Ugn–8 +
U8n-8-U8n–10

Transcribed Image Text:e2n cn
U8n-5 =
n-'(c – e)"(a – c)n
an-
U8n-4 =
bn-1 (d – f)"(b – d)"'
cn+1e2n
U8n-3 =
a" (a – c)"(c – e)n
dn+1 f2n
br (b – d)"(d – f)r'
e2n+1cn
U8n-2 =
U8n-1 =
a" (a – c)"(c – e)" '
f2n+1 d"
br (b – d)"(d – f)n '
cn+1e2n+1
U8n =
U8n+1 =
a" (c – e)*(a – c)-+I?
dn+1 f2n+1
b* (d – f)"(b – d)n+1*
U8n+2 =
This work aims to investigate the equilibria, local stability, global attractivity
and the exact solutions of the following difference equations
Bun-1un-5
Un+1 = QUn-1+
n = 0,1, ...,
(1)
Yun-3 - bun-5'
Bun-1un-5
run-3 + bun-5
where the coefficients a, B, y, and o are positive real numbers and the initial con-
ditions u; for all i = -5, -4, .., 0, are arbitrary non-zero real numbers. We also
Un+1 = aUn-1
-, n=0,1, ..,
(2)
present the numerical solutions via some 2D graphs.
2. ON THE EQUATION Un+1 = QUn-1+
Bun-1un-s
Yun-3-bun-s
This section is devoted to study the qualitative behaviors of Eq. (1). The
equilibrium point of Eq. (1) is given by
Un-1Un-5
Un+1 = Un-1+
n= 0, 1, ...,
(10)
Un-3 - Un-5
d" f2n-2
-1(6 – d)n-1(d – f)n-1'
e2n-1n-1
U8n-10 =
bn-1
U8n-9 =
an-1(a – c)n-1(c - e)n-1'
f2n-1an-1
bn-1 (b – d)n-1(d – f)n-1’
c"e2n-1
U8n-8 =
U8n-7 = -
an-1(c – e)n-1(a – c)n'
d" fan-1
bn-1(d – f)n-1(b – d)m*
U8n-6 =
Moreover, it can be seen from Eq. (10) that
U8n-6U8n-10
U8n-4 = U8n–6 +
U8n-8 - U8n–10
d" f2n-1
bn-1(d-f)n-1(b-d)n bn-1(6-d)n-1(d-f)n-I
f2n-1dn-1
d" f2n-2
d" f2n-1
br-1(d – f)"-1(b – d)"
dn f2n-2
bn-1(b-d)n-1(d-f)n-T
bn-1(b-d)n-T(d-f)n-T
d" f2n-1
b2-1(d – f)n-1(b – d)" bn-1(d – f)n-1(b – d)" (à – })
d" f2n-2
d" f2n-1
bn-1(d – f)n-1(b - d)" ™ br-1(d – f)"(b – d)n
dn+1 f2n-1
= -
+
br-1(d – f)"(b – d)n"
Expert Solution
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