E1= 18 V 0.5 2 R 2.5 0- R, a 6.0 2 R 1.5 0.5 0 E2 = 45 V

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Consider the circuit diagram in the figure.

A. What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure?

B. If the current through the middle part of the loop is I1 = 4.75 amps, what is the current through the top loop, I2, in amps?

### Electrical Circuit Diagram

The diagram above represents an electrical circuit featuring multiple components: resistors, batteries (emf sources), and current directions. This circuit can be used for educational purposes to explain the principles of electrical circuits, Ohm’s Law, and Kirchhoff's laws.

#### Components and Notation

- **Batteries (emf sources):**
  - \( \mathcal{E}_1 = 18 \, \text{V} \)
  - \( \mathcal{E}_2 = 45 \, \text{V} \)

- **Resistors:**
  - \( R_1 = 6.0 \, \Omega \)
  - \( R_2 = 2.5 \, \Omega \)
  - \( R_3 = 1.5 \, \Omega \)
  - Internal resistances \( r_1 = 0.5 \, \Omega \) and \( r_2 = 0.5 \, \Omega \)

#### Currents

- The diagram shows three branch currents:
  - \( I_1 \) runs through the path containing \( R_1 \).
  - \( I_2 \) is directed through the branch with \( \mathcal{E}_1 \) and \( R_2 \).
  - \( I_3 \) flows through \( \mathcal{E}_2 \) and through \( r_2 \).

#### Circuit Pathway

The circuit is a combination of series and parallel connections:

- The **left loop** consists of \( \mathcal{E}_1 \), \( r_1 \), and \( R_2 \).

- The **right loop** includes \( \mathcal{E}_2 \), \( r_2 \), and \( R_3 \).

- The **central loop** ties both batteries into \( R_1 \).

#### Analysis Approach

Using this diagram, students can apply:

- **Ohm’s Law** (\( V = IR \)) for each resistor and component.
  
- **Kirchhoff's Voltage Law** to each loop ensuring that the sum of electromotive forces (emf) and voltage drops equals zero.
  
- **Kirchhoff's Current Law** at junctions to understand current distribution.

This setup provides a practical illustration for solving circuit equations using these fundamental laws. Students can practice calculating individual currents and voltages across each
Transcribed Image Text:### Electrical Circuit Diagram The diagram above represents an electrical circuit featuring multiple components: resistors, batteries (emf sources), and current directions. This circuit can be used for educational purposes to explain the principles of electrical circuits, Ohm’s Law, and Kirchhoff's laws. #### Components and Notation - **Batteries (emf sources):** - \( \mathcal{E}_1 = 18 \, \text{V} \) - \( \mathcal{E}_2 = 45 \, \text{V} \) - **Resistors:** - \( R_1 = 6.0 \, \Omega \) - \( R_2 = 2.5 \, \Omega \) - \( R_3 = 1.5 \, \Omega \) - Internal resistances \( r_1 = 0.5 \, \Omega \) and \( r_2 = 0.5 \, \Omega \) #### Currents - The diagram shows three branch currents: - \( I_1 \) runs through the path containing \( R_1 \). - \( I_2 \) is directed through the branch with \( \mathcal{E}_1 \) and \( R_2 \). - \( I_3 \) flows through \( \mathcal{E}_2 \) and through \( r_2 \). #### Circuit Pathway The circuit is a combination of series and parallel connections: - The **left loop** consists of \( \mathcal{E}_1 \), \( r_1 \), and \( R_2 \). - The **right loop** includes \( \mathcal{E}_2 \), \( r_2 \), and \( R_3 \). - The **central loop** ties both batteries into \( R_1 \). #### Analysis Approach Using this diagram, students can apply: - **Ohm’s Law** (\( V = IR \)) for each resistor and component. - **Kirchhoff's Voltage Law** to each loop ensuring that the sum of electromotive forces (emf) and voltage drops equals zero. - **Kirchhoff's Current Law** at junctions to understand current distribution. This setup provides a practical illustration for solving circuit equations using these fundamental laws. Students can practice calculating individual currents and voltages across each
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