e. P(20.1286 < i < 21.8572) = f. Q1 for the i distribution = 8. P( h. For part c) and e), is the assumption of normal necessary? ONOO Yes z< 1050.0014) =

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NEED FULLY CORRECT HANDWRITTEN SOLUTION FOR THIS... ASAP!!!! i need part- e,f,g and h
3/21/22, 10:46 AM
PICASE GIVE TI 83 CAL CULATOR DIREct 0/11 pts 4 9
games are randomly selected. Round all answers to 4 decimal places where possible and assume a
The average score for games played in the NFL is 20.5 and the standard deviation is 9.2 points. 49
Question 1
LON
normal distribution.
ME 20.5
a What is the distribution of ä? a - N( 20,5.1.3143)
n- 49,
b. What is the distribution of
9.2
Jaq
r?
r- N(
c. P( > 19.2286) =
d. Find the 62th percentile for the mean score for this sample size
e. P(20.1286 < i < 21.8572) =
f. Q1 for the a distribution =
g. P(
h. For part c) and e), is the assumption of normal necessary? ONOO Yes
*< 1050.0014) =
Transcribed Image Text:3/21/22, 10:46 AM PICASE GIVE TI 83 CAL CULATOR DIREct 0/11 pts 4 9 games are randomly selected. Round all answers to 4 decimal places where possible and assume a The average score for games played in the NFL is 20.5 and the standard deviation is 9.2 points. 49 Question 1 LON normal distribution. ME 20.5 a What is the distribution of ä? a - N( 20,5.1.3143) n- 49, b. What is the distribution of 9.2 Jaq r? r- N( c. P( > 19.2286) = d. Find the 62th percentile for the mean score for this sample size e. P(20.1286 < i < 21.8572) = f. Q1 for the a distribution = g. P( h. For part c) and e), is the assumption of normal necessary? ONOO Yes *< 1050.0014) =
Given tho u 20-5,0:9.2,
n = 49
Ca) Mg= le = 20.5
149
1.3143
..xNN( 20.5 , [1. 3143
C6) Ex NN (nes, Ina)
nu=49 (a0.s)
1004.5
Imr= J49 (9.2)
: पि१
: G4.4
Ex oN (T0o4-s64.4)
1004.5
Cc) १ (४ >\9.२२86)
19.2286- 20.5
1.3143
-0.9674)
Z >
= 66 O.8333
(d) with P.valve : 0:6d -the cornesponding
COore
Z-SCore to
left is 0.3OSS
X- 20.5
0-3055 =
1.3143
X = 20.9015
Transcribed Image Text:Given tho u 20-5,0:9.2, n = 49 Ca) Mg= le = 20.5 149 1.3143 ..xNN( 20.5 , [1. 3143 C6) Ex NN (nes, Ina) nu=49 (a0.s) 1004.5 Imr= J49 (9.2) : पि१ : G4.4 Ex oN (T0o4-s64.4) 1004.5 Cc) १ (४ >\9.२२86) 19.2286- 20.5 1.3143 -0.9674) Z > = 66 O.8333 (d) with P.valve : 0:6d -the cornesponding COore Z-SCore to left is 0.3OSS X- 20.5 0-3055 = 1.3143 X = 20.9015
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