E. (kJ mol¹) 110.18 1.10 x 102 CALCULATING KAT 25.0 *C Use the equation of the line to calculate the Arrhenius pre-exponential factor A for this reaction, then calculate the rate constant k at 25.0 °C. y=-1.3252 x10x+33.985 Unrounded value Rounded value (3 s.f.) A(81) 5.7478x1014 5.75 x 1014 k(s) at 25.0°C 2.8603 x10-5 2.86 × 10-5 By showing the algebra for combining the Arrhenius equation with the expression for the half-life of a reaction of order zero, one or two, you should convince yourself that a plot of In(1/2) vs. 1/T will have a slope of +(E,/R) as long as the half-life is inversely related to the rate constant. Use this information to answer the following question. Does the proportionality constant between half-life and inverse rate constant affect the slope of a plot of In(2) vs. 1/T?: No For many reactions near room temperature, the rate and the rate constant approximately double for a 10 °C rise in temperature. What is the value of activation energy in kJ mol for such a reaction? Given two values of T near room temperature that differ by 10 *C, calculate the activation energy, E. T₁(K) T₁₂(K) 298.15 308.15 Unrounded value Rounded value (3 s.f.) E.(kJ mol¹)
E. (kJ mol¹) 110.18 1.10 x 102 CALCULATING KAT 25.0 *C Use the equation of the line to calculate the Arrhenius pre-exponential factor A for this reaction, then calculate the rate constant k at 25.0 °C. y=-1.3252 x10x+33.985 Unrounded value Rounded value (3 s.f.) A(81) 5.7478x1014 5.75 x 1014 k(s) at 25.0°C 2.8603 x10-5 2.86 × 10-5 By showing the algebra for combining the Arrhenius equation with the expression for the half-life of a reaction of order zero, one or two, you should convince yourself that a plot of In(1/2) vs. 1/T will have a slope of +(E,/R) as long as the half-life is inversely related to the rate constant. Use this information to answer the following question. Does the proportionality constant between half-life and inverse rate constant affect the slope of a plot of In(2) vs. 1/T?: No For many reactions near room temperature, the rate and the rate constant approximately double for a 10 °C rise in temperature. What is the value of activation energy in kJ mol for such a reaction? Given two values of T near room temperature that differ by 10 *C, calculate the activation energy, E. T₁(K) T₁₂(K) 298.15 308.15 Unrounded value Rounded value (3 s.f.) E.(kJ mol¹)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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