e. Calculate the upper fence

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Stats hw part 3
---

6. Use the following Stem and Leaf Plot to answer the following questions. Assume you have a sample and that the data is **not** bell-shaped.

(Sample) Variable: Gas $  
Key: 12 = 1.2

```
1 | 2
2 | 
3 | 
4 | 
5 | 
6 | 7
7 | 5 5
8 | 8 8
9 | 9
```

a. Use the above Stem and Leaf Plot and calculate the range.

b. Use the above Stem and Leaf Plot and calculate the **Quadratic Mean**.

c. **Calculate the upper fence**

--- 

This section of text provides a stem and leaf plot for a dataset, which is useful for quickly visualizing the distribution of a sample of data, in this case, gas prices. Each number is split into a stem, representing the leading digits, and a leaf, representing the last digit. The key indicates how to interpret the plot numbers. Despite missing data in stems 2 through 5, the plot shows values ranging from $1.2 to $9.9.

Questions prompt the calculation of the range, the quadratic mean (a measure of central tendency), and the upper fence (to detect potential outliers). 

---
Transcribed Image Text:--- 6. Use the following Stem and Leaf Plot to answer the following questions. Assume you have a sample and that the data is **not** bell-shaped. (Sample) Variable: Gas $ Key: 12 = 1.2 ``` 1 | 2 2 | 3 | 4 | 5 | 6 | 7 7 | 5 5 8 | 8 8 9 | 9 ``` a. Use the above Stem and Leaf Plot and calculate the range. b. Use the above Stem and Leaf Plot and calculate the **Quadratic Mean**. c. **Calculate the upper fence** --- This section of text provides a stem and leaf plot for a dataset, which is useful for quickly visualizing the distribution of a sample of data, in this case, gas prices. Each number is split into a stem, representing the leading digits, and a leaf, representing the last digit. The key indicates how to interpret the plot numbers. Despite missing data in stems 2 through 5, the plot shows values ranging from $1.2 to $9.9. Questions prompt the calculation of the range, the quadratic mean (a measure of central tendency), and the upper fence (to detect potential outliers). ---
**Question:**

4. Estimate the standard deviation.

d) Find the mean and standard deviation.

e) Find the percentage of data that is 4 standard deviations away from the mean. Provide the percentage and interval. Also, quote *the proper theorem* that allows for this prediction. Express your final answer in a sentence.

**Explanation:**

This set of questions involves statistical concepts:
- **Standard Deviation:** A measure of how spread out the numbers in a data set are.
- **Mean:** The average of a data set.
- **Theorem:** The use of a statistical theorem like Chebyshev’s Theorem or the Empirical Rule (68-95-99.7 rule) to determine the percentage of data within a certain number of standard deviations from the mean.

These concepts are fundamental in understanding data distribution and variability.
Transcribed Image Text:**Question:** 4. Estimate the standard deviation. d) Find the mean and standard deviation. e) Find the percentage of data that is 4 standard deviations away from the mean. Provide the percentage and interval. Also, quote *the proper theorem* that allows for this prediction. Express your final answer in a sentence. **Explanation:** This set of questions involves statistical concepts: - **Standard Deviation:** A measure of how spread out the numbers in a data set are. - **Mean:** The average of a data set. - **Theorem:** The use of a statistical theorem like Chebyshev’s Theorem or the Empirical Rule (68-95-99.7 rule) to determine the percentage of data within a certain number of standard deviations from the mean. These concepts are fundamental in understanding data distribution and variability.
Expert Solution
Step 1

Part 3: c.

The samples from Stem and leaf plot is 12, 55, 55, 78, 78, 89.

The position of first quartile value for even sample size is,

First quartileQ1=25100n+1thData value=251006+1thData value=1.75thData value

The first quartile is,

First quartileQ1=1stData value+0.752ndData value-1stData value=12+0.7555-12=44.25

The position of third quartile value for even sample size is,

Third quartileQ3=75100n+1thData value=751006+1thData value=5.25thData value

The third quartile is,

Third quartileQ3=5thData value+0.256thData value-5thData value=78+0.2589-78=80.75

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