e) Zs and zt, where z = xy – x²y, x = s + t, and y = s – t. [Ans:z, = 2s – 3s² – 2st + t²; z, = -s² – 2t + 2st + 3t²] %3D f) zg and zt, where z = e*+y, x = st, and y = s+t. [Ans:z, = (t + 1)est+s+t, z¢ = (s + 1)est+s+t] x-z g) Ws and wt, where w == x = s+t, y = st and z = s - t y+z -2t(t+1) 2s [Ans:w, (st+s-t)2i Wt = (st+s-t)2-

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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e) zs and zt, where z = xy – x²y, x = s + t, and y = s – t.
[Ans:z, = 2s – 3s² – 2st + t²; z; = -s² – 2t + 2st + 3t²]
%3D
f) Zs and zt, where z = e*+Y, x = st, and y = s +t.
[Ans:zs = (t + 1)est+s+t; z; = (s + 1)est+s+t]
X-z
g) Ws and wt,
where w =
y+z'
x = s+t, y = st and z =s - t
-2t(t+1)
2s
[Ans:ws
; Wt =
(st +s-t)2
(st+s-t)²
Transcribed Image Text:e) zs and zt, where z = xy – x²y, x = s + t, and y = s – t. [Ans:z, = 2s – 3s² – 2st + t²; z; = -s² – 2t + 2st + 3t²] %3D f) Zs and zt, where z = e*+Y, x = st, and y = s +t. [Ans:zs = (t + 1)est+s+t; z; = (s + 1)est+s+t] X-z g) Ws and wt, where w = y+z' x = s+t, y = st and z =s - t -2t(t+1) 2s [Ans:ws ; Wt = (st +s-t)2 (st+s-t)²
Find the following derivatives by using Chain Rule.
Transcribed Image Text:Find the following derivatives by using Chain Rule.
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