(e) x = = 2y², x = 4 + y² - (f) x = 1 — y², x = y² – 1 32 Answers (a), (b), (c) In 2-1, (d), (e) 33², (f) §.

Q: There's no -x+1/y-3 in the answers

A:

Q: -3(7a)

A: To evaluate-3(7a)

Q: 2(3y-6)/2=3y

A: 2(3y-6)/2=3y

Q: log (x*+3x +9) = 2

A:

Q: Add  (x3y2 + 4x2y3 + 3xy + 3) + (x2y3 + 4x3y2 + 3xy + 2 )

A: To add the expression

Q: y = -x - 5x + 6 and y = (x + 1)2 - 2 |

A:

Q: What is the value of x² + xy - 3y² - (5x² - xy + y²) -4x² + xy - 4y² ? Enter

A:

Q: If x=y, then 6+4(x-y)=

A: Here the given condition is x = y.That is, the value of x and y are same.

Q: 2(3q-9)=9-3q

A:

Q: 6 = -4(1 - x) + 3(x + 1)

A: Given:

Q: (2+1) x (9-?)=12

A: Just try to simplify and that's easy.

Q: 4(5+6)=

A: Given: 4(5+6)=

Q: 9(a + b) = 9a+

A: Given, 9(a + b) = 9a+

Q: 2y

A:

Q: what is (2 -4x)=1

A:

Q: 6(x+9)=2

A:

Q: verify that 3(A + B) = 3A + 3B

A:

Q: X=6{2+3[2(8-3)+(4+1)-2]}

A: Given,          x=62+328-3+4+1-2

Q: 2(7)+8y=23

A:

Q: (8,-1)+(2,1)

A:

Q: show that (AB)-1 = B-1A-1

A: Given matrix A has a order of 2x2 while matrix B has a order of 2x3.

Q: a. (X-3)² +(y-1)²=4  b.(X+3)² +y²=11

A: since the equation of circle having center (h,k) and radius r is given by (x-h)2+(y-k)2=r2    --(1)…

Q: -43 - 4r = 3(1 - 9r)

A:

Q: 2(4-3=10a+3

A:

Q: 2(15 + q)= blank + 2q

A: 2(15+q) =____________+2q Here we are suppose to find the value of blank.

Q: 5(2p-6)=40

A: To determine the value of p from the given equation.

Q: 8(7a+3)=304

A:

Q: (x+9)/8 = 5/4 +(x-3)/2

A: To calculate the value of x from the provided equation which is shown below,

Q: 1(3×+9)=7(8)=

A: Given  13x+9 = 78 ⇒3x+9= 7×8  ⇒3x+9= 56

Q: (10-3)(10+3)=

A: Given Expression. (10-3)(10+3)