e two wattmeter method: (Sen appendix B. WI Z. L30 L20 W2 W1 Vacla cos(30° – Oa) - W2 Vbela cos(30° + Ob) %3D I am trying to work out power using the two watt method. I have all the angles needed Vac and Vcb but I do not have Vbc, how can I work out W2 using Vcb? Would the cos(Angle) change? Vab=230

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e two wattmeter method: (Sen appendix B.
L1o
WI
ZL
L30-
L20
W2
W1
Vacla cos(30° – Oa)
%D
W2
Vbela cos(30° + Ob)
I am trying to work out power using the
two watt method.
I have all the angles needed Vac and Vcb
but I do not have Vbc, how can I work out
W2 using Vcb? Would the cos(Angle)
change?
Vab=230
Vcb=227
Vac=233
All phase angles are 80°
(phase angle between Va and la is 80
Phase angle between Vb and Ib is 80
Phase angle between Vb and Ib is 80)
Transcribed Image Text:e two wattmeter method: (Sen appendix B. L1o WI ZL L30- L20 W2 W1 Vacla cos(30° – Oa) %D W2 Vbela cos(30° + Ob) I am trying to work out power using the two watt method. I have all the angles needed Vac and Vcb but I do not have Vbc, how can I work out W2 using Vcb? Would the cos(Angle) change? Vab=230 Vcb=227 Vac=233 All phase angles are 80° (phase angle between Va and la is 80 Phase angle between Vb and Ib is 80 Phase angle between Vb and Ib is 80)
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