(e) This microprocessor uses the specifications shown in Figure Q1(e) for 16-bit floating point number representation. If the decimal value is 0.1875, determine the 16-bit floating point representation. The mantissa is normalised. A normalised mantissa has a logic 'I' after its binary point. E.g.. Normalised mantissa: 0.1xxxxxxx Non-normalised mantissa: 0.01xxxxxx Non-normalised mantissa: 0.001xxxxx Bit 15 8 bits Mantissa (M) is an unsigned fixed point fraction Decimal value 8 bits Exponent (E) is in 2's complement representation (0.M) - 2 Figure Ol(e)
(e) This microprocessor uses the specifications shown in Figure Q1(e) for 16-bit floating point number representation. If the decimal value is 0.1875, determine the 16-bit floating point representation. The mantissa is normalised. A normalised mantissa has a logic 'I' after its binary point. E.g.. Normalised mantissa: 0.1xxxxxxx Non-normalised mantissa: 0.01xxxxxx Non-normalised mantissa: 0.001xxxxx Bit 15 8 bits Mantissa (M) is an unsigned fixed point fraction Decimal value 8 bits Exponent (E) is in 2's complement representation (0.M) - 2 Figure Ol(e)
Chapter22: Sequence Control
Section: Chapter Questions
Problem 6SQ: Draw a symbol for a solid-state logic element AND.
Related questions
Question
Please give me correct solution.
![(e) This microprocessor uses the specifications shown in Figure Q1(e) for 16-bit floating
point number representation. If the decimal value is 0.1875, determine the 16-bit
floating point representation. The mantissa is normalised.
A normalised mantissa has a logic 'I' after its binary point. E.g.,
Normalised mantissa: 0.1xxxxxxx
Non-normalised mantissa: 0.01xxxxxx
Non-normalised mantissa: 0.001xxxxx
Bit 15
8 bits
Mantissa (M) is an unsigned
fixed point fraction
8 bits
Exponent (E) is in 2's
complement representation
Decimal value = (0.M)* 2
Figure 01(e)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa3f44898-6612-4caf-8e9b-cf86f85345c9%2F9e4902fb-258d-46cb-8db9-231b7093f2dd%2Fa739qc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(e) This microprocessor uses the specifications shown in Figure Q1(e) for 16-bit floating
point number representation. If the decimal value is 0.1875, determine the 16-bit
floating point representation. The mantissa is normalised.
A normalised mantissa has a logic 'I' after its binary point. E.g.,
Normalised mantissa: 0.1xxxxxxx
Non-normalised mantissa: 0.01xxxxxx
Non-normalised mantissa: 0.001xxxxx
Bit 15
8 bits
Mantissa (M) is an unsigned
fixed point fraction
8 bits
Exponent (E) is in 2's
complement representation
Decimal value = (0.M)* 2
Figure 01(e)
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
![Electric Motor Control](https://www.bartleby.com/isbn_cover_images/9781133702818/9781133702818_smallCoverImage.gif)
![Electric Motor Control](https://www.bartleby.com/isbn_cover_images/9781133702818/9781133702818_smallCoverImage.gif)