e thin glass shell shown in the figure (Figure 1) has a spherical ape with a radius of curvature of 10.5 cm, and both of its surfaces n act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the nter of the mirror along the optic axis, as shown in the figure. r related problemsolving tips and strategies, you may want to view Video Tutor Solution of Image formation by a concave mirror i. ure 3.30 mm 15.0 cm- < 1 of 1 > m = Part C Submit Suppose now that the shell is reversed. Find the location of the seed's image. Express your answer in centimeters. s'= -3.89 cm 8.08 cm 15.0 cm Part D ✓ Correct In part (c), the shell is a convex mirror. The magnitude of its focal length is the same as in part (a), but the sign reverses. When the glass is reversed, so the seed faces a convex surface, R = -10.5 cm. =-0.538. y' = my=-1.78 mm. The image is 8.08 cm to the left of the shell vertex and is 1.78 mm tall. Previous Answers R= -10.5 cm. s' =- |y' = (-10.5 cm)(15.0 cm) 30.0 cm+10.5 cm Find the height of the seed's image. Express your answer in milimeters. [V] ΑΣΦΑ Submit Request Answer -3.89 cm. ? Review I Constants mm

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Chapter1: Units, Trigonometry. And Vectors
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<Homework 8
Exercise 34.15 - Enhanced - with Solution
The thin glass shell shown in the figure (Figure 1) has a spherical
shape with a radius of curvature of 10.5 cm, and both of its surfaces
can act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the
center of the mirror along the optic axis, as shown in the figure.
For related problemsolving tips and strategies, you may want to view
a Video Tutor Solution of Image formation by a concave mirror i.
Figure
3.30 mm
K-15.0 cm
1 of 1
m = -
Part C
S
Suppose now that the shell is reversed. Find the location of the seed's image.
Express your answer in centimeters.
s' = -3.89 cm
Submit Previous Answers
Part D
8.08 cm
15.0 cm
Correct
In part (c), the shell is a convex mirror. The magnitude of its focal length is the same as in part (a), but the sign reverses.
When the glass is reversed, so the seed faces a convex surface, R = -10.5 cm.
R = -10.5 cm. s'
(-10.5 cm) (15.0 cm)
30.0 cm+10.5 cm
|y'| =
Submit
Find the height of the seed's image.
Express your answer in milimeters.
IVD ΑΣΦ
-0.538. y' = my = −1.78 mm. The image is 8.08 cm to the left of the shell vertex and is 1.78 mm tall.
Request Answer
= -3.89 cm.
?
mm
Constants
4 of 16
Review I
>
Transcribed Image Text:<Homework 8 Exercise 34.15 - Enhanced - with Solution The thin glass shell shown in the figure (Figure 1) has a spherical shape with a radius of curvature of 10.5 cm, and both of its surfaces can act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the center of the mirror along the optic axis, as shown in the figure. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Image formation by a concave mirror i. Figure 3.30 mm K-15.0 cm 1 of 1 m = - Part C S Suppose now that the shell is reversed. Find the location of the seed's image. Express your answer in centimeters. s' = -3.89 cm Submit Previous Answers Part D 8.08 cm 15.0 cm Correct In part (c), the shell is a convex mirror. The magnitude of its focal length is the same as in part (a), but the sign reverses. When the glass is reversed, so the seed faces a convex surface, R = -10.5 cm. R = -10.5 cm. s' (-10.5 cm) (15.0 cm) 30.0 cm+10.5 cm |y'| = Submit Find the height of the seed's image. Express your answer in milimeters. IVD ΑΣΦ -0.538. y' = my = −1.78 mm. The image is 8.08 cm to the left of the shell vertex and is 1.78 mm tall. Request Answer = -3.89 cm. ? mm Constants 4 of 16 Review I >
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