e that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground. Find the velocity of the ball after 5 seconds. Solution The difficulty in finding the velocity after 5 seconds is that we are dealing with a single instant of time (-5), so no time interval is involved. However, we can approximate the desired quantity by computing the average velocity over the brief time interval of a tenth of a second from t-tor-5.1. average velocity change in position time lapsed 8051)-83) 1

The velocity graph of a particle moving along a straight line is shown below. The velocity is given in feet per second and the time in seconds and positive velocity indicates the particle is moving to the right. Briefly explain each answer. (a) Find the change in position of the particle over the time interval from 0 to 10 seconds. (b) Find the total distance traveled by the particle of the particle over the time interval from 0 to 10 seconds..

A 30-second commercial during Super Bowl XXXVII in 2003 cost advertisers 2.2 million. For the first Super Bowl in 1967, an advertiser could have purchased approximately 26.19 minutes of advertising time for the same amount of money. (a) Assuming that advertising cost is proportional to its length of time, find the cost of advertising, in dollars/second, during the 2003 Super Bowl. cost= dollars/second. (round to nearest cent and do not enter commas) (b) Assuming that advertising cost is proportional to its length of time, find the cost of advertising, in dollars/second, during the 1967 Super Bowl. cost = dollars/second. (round to nearest cent and do not enter commas) (c) How many times more expensive was Super Bowl advertising in 2003 than in 1967? times more expensive (round to nearest whole number)