e tan e dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question

Use substitution to find each indefinite integral. 

Sure! Here are the transcriptions of the integrals:

1. \(\int e^{-x} \tan e^{-x} \, dx\)

2. \(\int x^4 \sec x^5 \tan x^5 \, dx\)

These integrals are presented as part of calculus exercises, focusing on integration techniques. The first integral involves an exponential function composed with a tangent function, and the second involves a polynomial function combined with trigonometric functions, specifically secant and tangent.
Transcribed Image Text:Sure! Here are the transcriptions of the integrals: 1. \(\int e^{-x} \tan e^{-x} \, dx\) 2. \(\int x^4 \sec x^5 \tan x^5 \, dx\) These integrals are presented as part of calculus exercises, focusing on integration techniques. The first integral involves an exponential function composed with a tangent function, and the second involves a polynomial function combined with trigonometric functions, specifically secant and tangent.
The integral presented is:

\[
\int 2x^7 \cos x^8 \, dx
\]

This is an expression that requires integration. The integrand includes a polynomial term \(2x^7\) and a trigonometric function \(\cos x^8\). To solve this integral, a common approach is using substitution, often facilitated by recognizing the derivative in the terms present (such as \(\cos x^8\) linked to \(\sin x^8\)). Proper substitution would simplify the integration process.
Transcribed Image Text:The integral presented is: \[ \int 2x^7 \cos x^8 \, dx \] This is an expression that requires integration. The integrand includes a polynomial term \(2x^7\) and a trigonometric function \(\cos x^8\). To solve this integral, a common approach is using substitution, often facilitated by recognizing the derivative in the terms present (such as \(\cos x^8\) linked to \(\sin x^8\)). Proper substitution would simplify the integration process.
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