(e) Suppose that a1 = aq+2 = a2q+3 = a3q+4 = A4q+5 = a5q+6 = A6q+7 = 0. By (d), we produce the following formulas below: II-, 2-(g+1)t-q II-o 2-(a+1)t-q +1 lim (7g+7)n+1 = lim 2-(7q+6) n-00 n00 n 7h 1 ΣΠ II-0 2-(4+1)k-(q+1)t-q +1 h=0 k=1 7h II-, 2-(9+1)t-q2-11+q 00 1 ΣΠ h=0 k-1 11-0 2-(q+1)k-(q+1)t-q+1 a1 = 2-(79+6) 1 II-, 2-(a+1)t-q+1 7h II-o 2-(q+1)t–-q +1 II-, 2-(a+1)t-q 1 ΣΠ h=0 k=111-0 2(a+1)k-(q+1)t-q +1 t=0 a1 = 0 > (3) 6
(e) Suppose that a1 = aq+2 = a2q+3 = a3q+4 = A4q+5 = a5q+6 = A6q+7 = 0. By (d), we produce the following formulas below: II-, 2-(g+1)t-q II-o 2-(a+1)t-q +1 lim (7g+7)n+1 = lim 2-(7q+6) n-00 n00 n 7h 1 ΣΠ II-0 2-(4+1)k-(q+1)t-q +1 h=0 k=1 7h II-, 2-(9+1)t-q2-11+q 00 1 ΣΠ h=0 k-1 11-0 2-(q+1)k-(q+1)t-q+1 a1 = 2-(79+6) 1 II-, 2-(a+1)t-q+1 7h II-o 2-(q+1)t–-q +1 II-, 2-(a+1)t-q 1 ΣΠ h=0 k=111-0 2(a+1)k-(q+1)t-q +1 t=0 a1 = 0 > (3) 6
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Show me the steps of determine green and information is here step by step. It complete
Transcribed Image Text:(e) Suppose that a1 = ag+2 = a2g+3 = a3q+4 = A4g+5 = a5q+6 = A6q+7 = 0. By (d), we
produce the following formulas below:
IL-o 2-(q+1)t-q
lim 2-(7q+6)
t=0
lim 2(7q+7)n+1
IT-o 2-(a+1)t-q+1
n-00
n-00
=0
n
7h
1
ΣΠ
2II T2-(g+1)k-(q+1)t-q †
h=0 k=1
It=0
II-, N-(a+1)t-q52-11+q I:
8.
7h
1
ΣΠ
IT-o 2-(a+1)k-(q+1)t-q + 1
It=0
a1 = 2-(7q+6)
1 -
II-, 2-(a+1)t-q+1
t=0
h=0 k=1
t=0
7h
+ 1
ΣΠ
h=0 k=111-0 S2(q+1)k-(q+1)t-q +1
-(q+1)t-q
1
a1 = 0 >
(3)
II-o 2-(a+1)t-q
t=0
6.
Transcribed Image Text:In this work, we deal with the following nonlinear difference equation
Im-(7g+6)
1+II-, Pm-(9+1)t-g
where 2-(79+6), N-(7q+5), .., N-1, o E (0, 00) is investigated.
Sm+1
= 0, 1,...,
(1)
m =
(e) If L(79+7)n+(t-1)q+t → a(t-1)q+t + 0 then 2(7g+7)n+6q+7 + 0 as n → o,
If S79+7)n+tg+t + arg+t +0 then 2(7g+7)n+79+7 → 0 as n -→ 0o. t = 1,6.
(d) We can generate the following formulas:
(7a+7)n+r(q+1)+s+1
(r-7)(g+1)+s+1 (1–
(mg+m-
m-1)+s)/S(r-7)(q+1)+s+1
1+ (ITm=12-(mq+m-1)+s)
n
7h+r
1
ΣΠ
IIm-1 Pla+1)t-(mq+m-1)+s +1
h=0 k=1
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