e) Sec^-1 (-2)= f) cot^-1 √3= g) cot(csc^-1(-3))= h) csc(cos^-1 7/25)= i) cos^-1 (cos(19π/6))= j) sin^-1 (sin 1.2)=

Q: Cos^-1 (cos(-60*)) Answer in degrees pls.

A: Solution is given below:

Q: Cos(75^•) sin (195^•) Cos(75 degree’s) Sin (195 degrees)

A: Given expression: cos75° sin195°cos75°sin195°

Q: find the value of sin^2(21degrees)+cos^2(21 degrees) - sin(70degrees)/cos(20degrees

A: the value of sin^2(21degrees)+cos^2(21 degrees) - sin(70degrees)/cos(20degrees

Q: cos^2 (100pi(t-1)) = cos^2 (200pi(t-1))/2 + 1/2 Is it correct?

A:

Q: (sin ^2x)(csc ^2x+sec ^2x)=sec ^2x

A:

Q: Solve the following equation involving inverse trig Sin^-1 (theta)+tan^-1 (theta)=0

A:

Q: 3tan^3(theta) = tan(theta)

A:

Q: ((sec^(2)x-1)(cotx))/(tanxsinx+cosx)

A:

Q: (x^2)cos^2 x - (x^2)sin^2 x = ? Is this a double-angle trigonometric identity?

A: we have evaluate the following . We can use double angle trigonometric identity

Q: csc tan ²¹ (-1)] = sec cos ¹ (-1/2) = -1

A: odd function even function

Q: Evalnate without using Calculator (^) Cos 2 () -9 (6) Sin 15°

A: a) We know that Therefore, we have

Q: Answer in term of "u" : cos(sin^(-1)(u))

A:

Q: solve each equation in the interval 0<=\theta <2\pi  a)sec^(2)\theta =4 b) sec((5\theta )/(2))=-2

A: solve each of the following equation in the interval 0≤θ&lt;2π (a) sec2θ=4 (b) sec5θ2=-2

Q: ((2+tan^2x)/sec^2x) -1 solve showing work

A:

Q: \begin{aligned}&amp;\text { b. } \sec 60^{\circ}=\frac{1}{\cos 60^{\circ}}=\frac{1}{1 /…

A: Value of sec 60

Q: sin sin 8

A:

Q: . is cos(cos^-1 1.7=1.7 true?     2. is sin^-1 (sin80*)=80* true?

A: We know the basic relations      cos(cos-1x)=x Because cos and cos-1 are opposite functions,…

Fundamentals of Trigonometric Identities

Trigonometric Identities are the equalities that involve trigonometry functions and hold for all the values of variables given in the equation.