E Paused Time interval Average velocity (m/s) EXAMPLE 3 Suppose that a ball is dropped from the upper observations deck of the CN Tower in Toronto, 450m above the ground. Find the velocity of the ball after 5 seconds. 5Sts6 53.9 5sts 5.1 49.49 SOLUTION Through experiments carried out four centuries ago, Galileo discovered that the distance fallen by any freely falling body is proportional to the square of the time it has been falling. (This model for free fall neglects air resistance.) If the distance fallen after t seconds is denoted by s(t) and measured in meters, then Galileo's law is expressed by the equation 5Sts 5.05 49.245 5sts 5.01 49.049 5 sts 5.001 49.0049 Video Example) s(t) = 4.9t %3D Tutorial The difficulty in finding the velocity after 5 s is that we are dealing with a single instant of time (t = 5), so no time interval is involved. However, we can approximate the desired quantity by computing the average velocity over the brief interval of a tenth of a second from t = 5 to t = 5.1: Online Textbook change in position average velocity = time elapsed s(5.1) - s(5) 0.1 4.9(5.1 2-4.9( 0.1 The table shows the results of similar calculations of the average velocity over successively smaller time periods. It appears that as we shorten the time period, the average velocity is becoming closer to m/s. The instantaneous velocity when t = 5 is defined to be the limiting value of these average velocities over shorter and shorter time periods that start at t= 5. Thus the (instantaneous) velocity after 5

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
icon
Concept explainers
Question
Average velocity
3 Logout Succes x
O
Microsoft Offic X
O Mail - Rojas, Br x
HiSyllabus - 202 x
Bb General Syllab x
A HW 01 (Sectio x
webassign.net/web/Student/Assignment-Responses/submit?dep=25609279&tags=autosave#question3904441 1
* Cengage Digit x
* Cengage Lear x
+
Time
E Paused
Average
velocity (m/s)
interval
EXAMPLE 3 Suppose that a ball is dropped from the upper observations deck of the CN Tower in
Toronto, 450m above the ground. Find the velocity of the ball after 5 seconds.
5sts6
53.9
5stS 5.1
49.49
SOLUTION Through experiments carried out four centuries ago, Galileo discovered that the distance
fallen by any freely falling body is proportional to the square of the time it has been falling. (This model for
free fall neglects air resistance.) If the distance fallen after t seconds is denoted by s(t) and measured in
meters, then Galileo's law is expressed by the equation
5sts 5.05
49.245
5Sts 5.01
49.049
5sts 5.001
49.0049
Video Example)
s(t) = 4.9t
Tutorial
The difficulty in finding the velocity after 5 s is that we are dealing with a single instant of time (t = 5), so
no time interval is involved. However, we can approximate the desired quantity by computing the average
velocity over the brief interval of a tenth of a second from t = 5 to t = 5.1:
Online Textbook
change in position
average velocity =
time elapsed
s(5.1) - s(5)
%3!
0.1
4.9( 5.1
)²-4.9(
0.1
The table shows the results of similar calculations of the average velocity over successively smaller time
periods.
It appears that as we shorten the time period, the average velocity is becoming closer to
m/s. The instantaneous velocity when t = 5 is defined to be the limiting value of these average
velocities over shorter and shorter time periods that start at t = 5. Thus the (instantaneous) velocity after 5
s is
m/s
10:19 PM
(?
A A 40)
2/18/2021
W
a
P Type here to search
hp
end
pa up
home
ins
delete
ort sc
Transcribed Image Text:3 Logout Succes x O Microsoft Offic X O Mail - Rojas, Br x HiSyllabus - 202 x Bb General Syllab x A HW 01 (Sectio x webassign.net/web/Student/Assignment-Responses/submit?dep=25609279&tags=autosave#question3904441 1 * Cengage Digit x * Cengage Lear x + Time E Paused Average velocity (m/s) interval EXAMPLE 3 Suppose that a ball is dropped from the upper observations deck of the CN Tower in Toronto, 450m above the ground. Find the velocity of the ball after 5 seconds. 5sts6 53.9 5stS 5.1 49.49 SOLUTION Through experiments carried out four centuries ago, Galileo discovered that the distance fallen by any freely falling body is proportional to the square of the time it has been falling. (This model for free fall neglects air resistance.) If the distance fallen after t seconds is denoted by s(t) and measured in meters, then Galileo's law is expressed by the equation 5sts 5.05 49.245 5Sts 5.01 49.049 5sts 5.001 49.0049 Video Example) s(t) = 4.9t Tutorial The difficulty in finding the velocity after 5 s is that we are dealing with a single instant of time (t = 5), so no time interval is involved. However, we can approximate the desired quantity by computing the average velocity over the brief interval of a tenth of a second from t = 5 to t = 5.1: Online Textbook change in position average velocity = time elapsed s(5.1) - s(5) %3! 0.1 4.9( 5.1 )²-4.9( 0.1 The table shows the results of similar calculations of the average velocity over successively smaller time periods. It appears that as we shorten the time period, the average velocity is becoming closer to m/s. The instantaneous velocity when t = 5 is defined to be the limiting value of these average velocities over shorter and shorter time periods that start at t = 5. Thus the (instantaneous) velocity after 5 s is m/s 10:19 PM (? A A 40) 2/18/2021 W a P Type here to search hp end pa up home ins delete ort sc
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Continuous Probability Distribution
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,