e) None the above. ≤0.92 then , 23. From the design point of view, if, ()+[(M) + (M)] ≤ the member can be considered to be: a) Satisfactory but overdesigned. b) Satisfactory but under designed. c) Satisfactory. d) Not satisfactory. e) Satisfactory and Economic. 24. The application of the effective axial load design method provides economical beam-column design, unless the moments becomes: quite large the axial load and bending moments are replaced with an imaginary concentric load that represents: a) Quite large in comparison with the shear loads. b) Quite large in comparison with the axial loads. c) Quite small in comparison with the shear loads. d) Quite small in comparison with the axial loads. e) None the above. 25.Using Table 11-3, entitled "Preliminary Beam-Column Design", using the LRFD method, Fy = 50 ksi, KL = 24 ft, Pu = 200 k, Mux = 100 k.ft, and Muy = 50 k.ft. Determine u, m, and the estimated equivalent axial load for a W10- shaped beam-column section: Use: Pueq = Pu+Muxm + Muymu a) 2, 1.3, 460 k. b) 2, 1.4, 460 k. c) 1, 1.2, 420 k. d) 1, 1.3, 480 k. e) None the above.
e) None the above. ≤0.92 then , 23. From the design point of view, if, ()+[(M) + (M)] ≤ the member can be considered to be: a) Satisfactory but overdesigned. b) Satisfactory but under designed. c) Satisfactory. d) Not satisfactory. e) Satisfactory and Economic. 24. The application of the effective axial load design method provides economical beam-column design, unless the moments becomes: quite large the axial load and bending moments are replaced with an imaginary concentric load that represents: a) Quite large in comparison with the shear loads. b) Quite large in comparison with the axial loads. c) Quite small in comparison with the shear loads. d) Quite small in comparison with the axial loads. e) None the above. 25.Using Table 11-3, entitled "Preliminary Beam-Column Design", using the LRFD method, Fy = 50 ksi, KL = 24 ft, Pu = 200 k, Mux = 100 k.ft, and Muy = 50 k.ft. Determine u, m, and the estimated equivalent axial load for a W10- shaped beam-column section: Use: Pueq = Pu+Muxm + Muymu a) 2, 1.3, 460 k. b) 2, 1.4, 460 k. c) 1, 1.2, 420 k. d) 1, 1.3, 480 k. e) None the above.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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