(e) None of the above Problem 6. Let 1 3 1 67 -2 -2 -4 0 0 -5 6 -1 7 -2 0 2 Does the equation Ax = b have a solution for each b in R4? A= (a) Yes, because the reduced row echelon form of A does not have a row of the form [0 0 b] with b nonzero. (b) Yes, because the columns of A do not span R¹. (c) No, because A does not have a pivot position in every row. (d) No, because each b in R¹ is a linear combination of the columns of A. (e) None of the above ...
(e) None of the above Problem 6. Let 1 3 1 67 -2 -2 -4 0 0 -5 6 -1 7 -2 0 2 Does the equation Ax = b have a solution for each b in R4? A= (a) Yes, because the reduced row echelon form of A does not have a row of the form [0 0 b] with b nonzero. (b) Yes, because the columns of A do not span R¹. (c) No, because A does not have a pivot position in every row. (d) No, because each b in R¹ is a linear combination of the columns of A. (e) None of the above ...
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:(e) None of the above
Problem 6. Let
3 1 6
-2 -4 0
0
-5 6
-1 7
2
Does the equation Ax = b have a solution for each b in R4?
1
-2
-2
0
A =
DELL
(a) Yes, because the reduced row echelon form of A does not have a row of the form
0 b with b nonzero.
(b) Yes, because the columns of A do not span R¹.
(c) No, because A does not have a pivot position in every row.
(d) No, because each b in R4 is a linear combination of the columns of A.
(e) None of the above
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