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e monthly cost of driving a car depends on the number of miles driven. Lynn found that in May it cost her $438 to drive 420 mi and in June it cost her $558 to drive 720 mi. (a) Express the monthly cost C as a function of the distance driven d, assuming that a linear relationship gives a suitable model. C(d) = (b) Use part (a) to predict the cost of driving 1700 miles per month. $ (c) Draw the graph of the linear function. с 1000 000 с 1000 000

e monthly cost of driving a car depends on the number of miles driven. Lynn found that in May it cost her $438 to drive 420 mi and in June it cost her $558 to drive 720 mi. (a) Express the monthly cost C as a function of the distance driven d, assuming that a linear relationship gives a suitable model. C(d) = (b) Use part (a) to predict the cost of driving 1700 miles per month. $ (c) Draw the graph of the linear function. с 1000 000 с 1000 000

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May it cost her $438 to drive 420 mi and in June it cost her $558 to drive 720 mi. (a) Express the monthly cost C as a function of the distance driven d, assuming that a linear relationship gives a suitable model. C(d) = (b) Use part (a) to predict the cost of driving 1700 miles per month. $ (c) Draw the graph of the linear function. C с O 1000 800 600 O 400 200 1000 800 600 400 200 200 400 600 200 400 800 1000 600 d 1000 800 LL 600 400 200 800 1000 1000 800 600 400 200 200 400 U 600 800 1000 200 400 600 800 1000 d d
Transcribed Image Text:The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May it cost her $438 to drive 420 mi and in June it cost her $558 to drive 720 mi. (a) Express the monthly cost C as a function of the distance driven d, assuming that a linear relationship gives a suitable model. C(d) = (b) Use part (a) to predict the cost of driving 1700 miles per month. $ (c) Draw the graph of the linear function. C с O 1000 800 600 O 400 200 1000 800 600 400 200 200 400 600 200 400 800 1000 600 d 1000 800 LL 600 400 200 800 1000 1000 800 600 400 200 200 400 U 600 800 1000 200 400 600 800 1000 d d
What does the slope represent? O It represents the cost (in dollars) per mile. It represents the distance (in miles) traveled. It represents the cost (in dollars) of driving. It represents the fixed cost (amount she pays even if she does not drive). 2 (d) What does the C-intercept represent? It represents the fixed cost (amount she pays even if she does not drive). It represents the cost (in dollars) per mile. It represents the distance (in miles) traveled. It represents the cost (in dollars) of driving. (e) Why does a linear function give a suitable model in this situation? O A linear function is suitable because the monthly cost increases even if the miles driven is constant. A linear function is suitable because the monthly cost is fixed despite the fact that the miles driven may vary. A linear function is suitable because the monthly cost increases as the number of miles driven increases. A linear function is suitable because the monthly cost increases as the number of miles driven decreases. d Help? D
Transcribed Image Text:What does the slope represent? O It represents the cost (in dollars) per mile. It represents the distance (in miles) traveled. It represents the cost (in dollars) of driving. It represents the fixed cost (amount she pays even if she does not drive). 2 (d) What does the C-intercept represent? It represents the fixed cost (amount she pays even if she does not drive). It represents the cost (in dollars) per mile. It represents the distance (in miles) traveled. It represents the cost (in dollars) of driving. (e) Why does a linear function give a suitable model in this situation? O A linear function is suitable because the monthly cost increases even if the miles driven is constant. A linear function is suitable because the monthly cost is fixed despite the fact that the miles driven may vary. A linear function is suitable because the monthly cost increases as the number of miles driven increases. A linear function is suitable because the monthly cost increases as the number of miles driven decreases. d Help? D
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