e mass of pure aluminum produced.

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In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AlF), resulting in
the reduction of the Al,O, to pure aluminum.
Suppose a current of 690. A is passed through a Hall-Heroult cell for 23.0 seconds. Calculate the mass of pure aluminum produced.
Be sure your answer has a unit symbol and the correct number of significant digits.
Explanation
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Transcribed Image Text:In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AlF), resulting in the reduction of the Al,O, to pure aluminum. Suppose a current of 690. A is passed through a Hall-Heroult cell for 23.0 seconds. Calculate the mass of pure aluminum produced. Be sure your answer has a unit symbol and the correct number of significant digits. Explanation Check 02022 McGraw Hill LLC All Rights Reserved Terms of Use I Privacy Center Accessibility CHI MIL Y Type here to search 99+ BOok F9 FIO F12 IA Pn Sc Insert F3 F5 F7 F8 F1O F6 FI F2 F4 & %23 olo
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