(e) Let X = [0, 1] U [2, 3] with the subspace topology of the real line. Then A = [0, 1] and B = [2, 3] are disjoint, non-empty open subsets of X for which X = A U B, so X is disconnected. (Note that A and B are relatively open since A = (-∞, 3/2) N X and B = (3/2, ∞0) n X.) (f) Let X denote the set of real nụmbers with the one additional point a = (0, 1), and let the topology T for X consist of Ø and all subsets of X which contain a. Then there do not exist two disjoint non-empty open sets, so X is connected. Note that as a subspace of (X, T ), R is assigned the discrete topology and is therefore disconnected. This example (as well as examples (c), (d), and (e) above) demonstrate that the property of being connected is definitely not hereditary. %3D
(e) Let X = [0, 1] U [2, 3] with the subspace topology of the real line. Then A = [0, 1] and B = [2, 3] are disjoint, non-empty open subsets of X for which X = A U B, so X is disconnected. (Note that A and B are relatively open since A = (-∞, 3/2) N X and B = (3/2, ∞0) n X.) (f) Let X denote the set of real nụmbers with the one additional point a = (0, 1), and let the topology T for X consist of Ø and all subsets of X which contain a. Then there do not exist two disjoint non-empty open sets, so X is connected. Note that as a subspace of (X, T ), R is assigned the discrete topology and is therefore disconnected. This example (as well as examples (c), (d), and (e) above) demonstrate that the property of being connected is definitely not hereditary. %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Justify the examples (e) and (f) in details

Transcribed Image Text:Definition: A topological space X is disconnected or separated if it is the union
of two disjoint, non-empty open sets. Such a pair A, B of subsets of X is called a
separation of X. A space X is connected provided that it is not disconnected. In other
words, X is connected if there do not exist open subsets A and B of X such that
A + Ø, B+ Ø, ANB= Ø, AUB= X.
%3D
A subspace Y of X is connected provided that it is a connected space when
assigned the subspace topology. The terms connected set and connected subset are
sometimes used to mean connected space and connected subspace, respectively.
![(e) Let X = [0, 1] U [2, 3] with the subspace topology of the real line.
Then A = [0, 1] and B = [2, 3] are disjoint, non-empty open subsets
of X for which X = A U B, so X is disconnected. (Note that A and B
are relatively open since A = (-∞, 3/2) n X and B = (3/2, ∞0) n X.)
(f) Let X denote the set of real nụmbers with the one additional point
a = (0, 1), and let the topology T for X consist of Ø and all subsets
of X which contain a. Then there do not exist two disjoint non-empty
open sets, so X is connected. Note that as a subspace of (X, T ), R is
assigned the discrete topology and is therefore disconnected. This
example (as well as examples (c), (d), and (e) above) demonstrate that
the property of being connected is definitely not hereditary.
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa279d709-2503-4944-8ec2-0472e9533efc%2F61806089-63a9-4098-92ca-dcca3a8e3e60%2Fcyrenko_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(e) Let X = [0, 1] U [2, 3] with the subspace topology of the real line.
Then A = [0, 1] and B = [2, 3] are disjoint, non-empty open subsets
of X for which X = A U B, so X is disconnected. (Note that A and B
are relatively open since A = (-∞, 3/2) n X and B = (3/2, ∞0) n X.)
(f) Let X denote the set of real nụmbers with the one additional point
a = (0, 1), and let the topology T for X consist of Ø and all subsets
of X which contain a. Then there do not exist two disjoint non-empty
open sets, so X is connected. Note that as a subspace of (X, T ), R is
assigned the discrete topology and is therefore disconnected. This
example (as well as examples (c), (d), and (e) above) demonstrate that
the property of being connected is definitely not hereditary.
%3D
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