E) I/resistor on the load is a) 2A b) 4A c) 6.93A d) 12A F) I-line on the low side is a) 2A b) 4A c) 6.93A d) 12A G) I-phase on the low side is a) b) c) d) 12A 2A 4A 6.93A H) I/coil on the low side is a) 2A b) 4A с) 6.93A d) 12A I) I-phase on the high side is a) b) 1.73A с) 2A d) 4A 1A J) I-line on the high side is a) 1A b) 1.73A c) 2A d) 4A

What conclusions we come up with after doing open circuit test on single phase transformer.

(a) Using Faraday's Law as a starting point prove that the maximum operating voltage of a transformer to avoid magnetic saturation is given by the following equation: Q3 Vrms=4.44N.f.Bmax.Ac where: Vrms = maximum rms operating voltage avoiding magnetic saturation N = number of turns in the winding f= electrical frequency (Hz) Bmax = maximum flux density (T) (typically 1.3T for iron) Ac = Iron core cross sectional area (m²) A single phase transformer has the parameters shown on Table Q3 and is connected to a 230 V and 50 Hz AC supply. Sketch the equivalent circuit and using this determine: (b) (i) The Secondary voltage under Open Circuit (Vsoc) (ii) The Secondary voltage, current and power (W) given a 0.6 Q resistive Load. (iii) The efficiency and voltage regulation at this load Through suitable calculations determine whether the size, weight or cost of this transformer could be reduced such that it operated below a maximum flux density of 1.3 T and the current density in both windings…

(B)-Explain by drawing the change in the direction of current flows through coils at the ideal case of commutation by considering coil B which is the coil under commutation as shown in the figure below. B C 5A SA 5A Armature winding 10 A Commutator 10 A Brush