(e) Given that the general solution of the partial differential equation and boundary conditions may be expressed as (2η 1)ππ -ΣC₁ exp(-D(2n=1³4²¹) com (2n = 1)*²) COS 2L n=1 θ(x,t) = Σ Cn exp find the particular solution that satisfies the given initial temperature distribution.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Question
The temperature distribution 0(x, t) along an insulated metal rod of
length L is described by the differential equation
2²0 1 00
əx² D Ət
0(x,0) = 0.3 cos
(0<x<L, t> 0),
where D0 is a constant. The rod is held at a fixed temperature of 0°C at
one end and is insulated at the other end, which gives rise to the boundary
L for
conditions = 0 when x = 0 for t> 0 together with 0 = 0 when x =
t> 0.
20
əx
The initial temperature distribution in the rod is given by là coitulos
(0 ≤ x ≤ L).
(17)
2 L
(2 in U
dram 1
upe
Transcribed Image Text:The temperature distribution 0(x, t) along an insulated metal rod of length L is described by the differential equation 2²0 1 00 əx² D Ət 0(x,0) = 0.3 cos (0<x<L, t> 0), where D0 is a constant. The rod is held at a fixed temperature of 0°C at one end and is insulated at the other end, which gives rise to the boundary L for conditions = 0 when x = 0 for t> 0 together with 0 = 0 when x = t> 0. 20 əx The initial temperature distribution in the rod is given by là coitulos (0 ≤ x ≤ L). (17) 2 L (2 in U dram 1 upe
(e) Given that the general solution of the partial differential equation and
boundary conditions may be expressed as
(2η - 1)πα
D(2n-1)²²t\
bahw
4L²
2L
11 nobon
find the particular solution that satisfies the given initial temperature
distribution.
[C₁ exp(- 7²4).
COS
alni no
n=1
0(x,t) = Σ Cn exp
TI
Transcribed Image Text:(e) Given that the general solution of the partial differential equation and boundary conditions may be expressed as (2η - 1)πα D(2n-1)²²t\ bahw 4L² 2L 11 nobon find the particular solution that satisfies the given initial temperature distribution. [C₁ exp(- 7²4). COS alni no n=1 0(x,t) = Σ Cn exp TI
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