e following systems, the origin is the equilibrium point. dž Write each system in matrix form = Ax. dt Determine the eigenvalues of A. State whether the origin is a stable or unstable equilib State whether the origin is a node, saddle point, spiral State the equations of the straight-line trajectories an towards or away from the origin. If none exist, state s If A has real eigenvalues, then determine the eigenvec solve the system. (See examples in Section 7.4) dx = 4x - 13y dt dy = 2x - 6y dt

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.7: The Inverse Of A Matrix
Problem 32E
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Parts B, E, F. I attached a photo of the answered parts. 

For the following systems, the origin is the equilibrium point.
dx
a) Write each system in matrix form = Ax.
dt
b)
Determine the eigenvalues of A.
c) State whether the origin is a stable or unstable equilibrium.
d) State whether the origin is a node, saddle point, spiral point, or center.
e) State the equations of the straight-line trajectories and tell whether they are going
towards or away from the origin. If none exist, state so.
f) If A has real eigenvalues, then determine the eigenvectors and use diagonalization to
solve the system. (See examples in Section 7.4)
3.
dx
dt
dt
= 4x - 13y
= 2x - 6y
Transcribed Image Text:For the following systems, the origin is the equilibrium point. dx a) Write each system in matrix form = Ax. dt b) Determine the eigenvalues of A. c) State whether the origin is a stable or unstable equilibrium. d) State whether the origin is a node, saddle point, spiral point, or center. e) State the equations of the straight-line trajectories and tell whether they are going towards or away from the origin. If none exist, state so. f) If A has real eigenvalues, then determine the eigenvectors and use diagonalization to solve the system. (See examples in Section 7.4) 3. dx dt dt = 4x - 13y = 2x - 6y
dx
3) de
a)
a
1>
dy
dt
= 4x-13
F) stable
2x-6y
A = [
2
2
4
-120
d (x)
-13
[2²] [23] [4]
2]
ما
Transcribed Image Text:dx 3) de a) a 1> dy dt = 4x-13 F) stable 2x-6y A = [ 2 2 4 -120 d (x) -13 [2²] [23] [4] 2] ما
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