E F= -> Tgc Cos 45 - T84 Cos O = > Ter Cos 45 - TBA Ces 0 = (T. os 45-T Be %3D To sin 45 BC T sin45- (6ox9.81) = 0 ->

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E Fx=0 -> Te Cos 45 - Tg4 (Ta Cos 45- Ta'
Cos 0 = >
BC
Z Fy = •
To sin 45
Bc
Ta sin45- (60x9.81)= 0
->
BC
Transcribed Image Text:E Fx=0 -> Te Cos 45 - Tg4 (Ta Cos 45- Ta' Cos 0 = > BC Z Fy = • To sin 45 Bc Ta sin45- (60x9.81)= 0 -> BC
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