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e explain how the answer on the right was obtained

e explain how the answer on the right was obtained

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Please explain how the answer on the right was obtained

To calculate for the electric field E , integrate dE across all charges (the whole length of the rod; x = 0→ L), where Adx dĒ = k (L + D – x )² ^ dx E = kl all charges (L +D – x )² dx E = kì 1 Jo (L + D – x )² E = kl D î D + L Let u = L + D – x
Transcribed Image Text:To calculate for the electric field E , integrate dE across all charges (the whole length of the rod; x = 0→ L), where Adx dĒ = k (L + D – x )² ^ dx E = kl all charges (L +D – x )² dx E = kì 1 Jo (L + D – x )² E = kl D î D + L Let u = L + D – x
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