(e) Example 2-8. The space time required to achieve 80% conversion in a CSTR is 5 h. The entering volumetric flow rate and concentration of reactant A are 1 dm³/min and 2.5 molar, respectively. If possible, deter- mine (1) the rate of reaction, -A= (2) the reactor volume, V = and (4) the PFR 1 (3) the exit concentration of A, CA = space time for 80% conversion.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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2.8

**Example 2-8:**

The space time required to achieve 80% conversion in a Continuous Stirred-Tank Reactor (CSTR) is 5 hours. The entering volumetric flow rate and concentration of reactant A are 1 dm³/min and 2.5 molar, respectively. If possible, determine:

1. The rate of reaction, \(-r_A =\) ____.
2. The reactor volume, \(V =\) ____.
3. The exit concentration of A, \(C_A =\) ____.
4. The Plug Flow Reactor (PFR) space time for 80% conversion.

**Given Values:**

\[
C_{A0} = 0.2 \, \frac{\text{mol}}{\text{dm}^3} \quad \& \quad F_{A0} = 0.4 \, \frac{\text{mol}}{\text{s}}
\]

**Formulas:**

- Space time:
  \[
  \tau = \frac{V}{v_0} = \, \, [ \, \, ] 
  \]

- Space velocity:
  \[
  SV = \frac{1}{\tau}
  \]

There are no graphs or diagrams to further explain in this section.
Transcribed Image Text:**Example 2-8:** The space time required to achieve 80% conversion in a Continuous Stirred-Tank Reactor (CSTR) is 5 hours. The entering volumetric flow rate and concentration of reactant A are 1 dm³/min and 2.5 molar, respectively. If possible, determine: 1. The rate of reaction, \(-r_A =\) ____. 2. The reactor volume, \(V =\) ____. 3. The exit concentration of A, \(C_A =\) ____. 4. The Plug Flow Reactor (PFR) space time for 80% conversion. **Given Values:** \[ C_{A0} = 0.2 \, \frac{\text{mol}}{\text{dm}^3} \quad \& \quad F_{A0} = 0.4 \, \frac{\text{mol}}{\text{s}} \] **Formulas:** - Space time: \[ \tau = \frac{V}{v_0} = \, \, [ \, \, ] \] - Space velocity: \[ SV = \frac{1}{\tau} \] There are no graphs or diagrams to further explain in this section.
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