(e) Construct and interpret a 95% confidence interval for the population proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom. Select the correctchoice below and fill in any answer boxes within your choice.(Type integers or decimals rounded to three decimal places as needed. Use ascending order.)OA. We are % confident the proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom is between and.OB. There is a% probability the proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom is between and. In a survey conducted by a reputable marketing agency, 252 of 1000 adults 19 years of age or older confessed to bringing and using their cell phone every trip to the bathroom

From the provided information, Sample size (n) = 1000 From which 252 confessed to be bringing and…

Answered: (e) Construct and interpret a 95%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the given degree of confidence and sample data to construct a confidence interval for the population mean u. Round your final answers to the nearest hundredth. Test scores: n = 104, x = 95.3, o = 6.5; 99% confidence You will need to calculate the margin of error, followed by the lower and upper end of the confidence interval. Margin of Error: choose your answer.. Confidence Interval: choose your answer... レ choose your answer...
A poll of 2338 U.S. adults found that 71% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to %
Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1004 and x = 575 who said "yes." Use a 90% confidence level. E Click the icon to view a table of z scores. .... a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.)
A survey was conducted that asked 1013 people how many books they had read in the past year. Results indicated that x=10.3 books and s=16.6books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) A. There is a 90% probability that the true mean number of books read is between ___ and ____ B. There is 90% confidence that the population mean number of books read is between ___ and ____. C. If repeated samples are taken, 90% of them will have a sample mean between ___ and ___.
Name: Statistics 1. An investigative reporter contacts a random sample of hotels, and finds a 95% confidence interval for the proportion of hotels in the United States that have reported having bedbugs is (0.04, 0.11). a. Interpret this confidence interval in context. F3 80 b. A national hospitality organization had reported that only 5% of hotels have experienced problems with bedbugs. Does this reporter have compelling evidence that the true proportion is really higher? Explain. c. How could the reporter estimate this proportion with a smaller margin of error? a. Identify the parameter, p, 2. To estimate how often someone runs a red light in Cyber City, a student watched traffic for a while at several randomly selected intersections. Drivers ran the red light during 43 of 240 light changes she observed. Q O Period: Quiz (ch 16+17) F4 9 F5 Page 1 / 2 c F6 8 + F7 Date: : DII F8 DD F9
A researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 480 college students showed that 23% of them had, or intended to, cheat on examinations. Find the 95% confidence interval for the population proportion. Round to four decimal places.
The figure to the right shows the results of a survey in which 2000 college graduates from the year 2016 were asked questions about employment. Construct 99% confidence intervals for the population proportion of college students who gave each response. Employment College students' responses to questions about employment Expect to stay at first employer for 3 or more years Completed an apprenticeship or intemship 70% 66% Employed in field of study 61% Feel underemployed 46% Prefer to work for a large company 15% The 99% confidence interval for the proportion of college students that expect to stay at their first employer for 3 or more years is (Round to three decimal places as needed.)
The figure to the right shows the results of a survey in which 2000 college graduates from the year 2016 were asked questions about employment. Construct 99% confidence intervals for the population proportion of college students who gave each response. Employment College students' responses to questions about employment Expect to stay at first employer for 3 or more years Completed an apprenticeship or internship 70% 66% Employed in field of study 61% Feel underemployed 46% Prefer to work for a large company 15% The 9970 Conuenit initivaliui int proportion un cuiityt diuutid inal txptul iu diay al ineli idi empivyti iui j'ui muit years is (0.01, 0.121). (Round to three decimal places as needed.) The 99% confidence interval for the proportion of college students that have completed an apprenticeship or internship is (J.). (Round to three decimal places as needed.)
form a confidence interval for mean, proportion, and standard deviation.
A random sample of 800 home owners in a particular city found 208 home owners who had a swimming pool in their backyard. Find a 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard. Express your results to the nearest hundredth of a percent. Answer: ☐ t to %

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