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e) C) modulus of d) Argument of 3+4i K = 0, 1, 2, 3, 4 roots for WK K (5) ½ se i (ton+ (1/3))/5 ws Wo Wo = 1.356069 + 0.25 4419 i W₁ = 0.177 08171 + 1.3683186 i W₂ = -1.2466 2713 + 0-59124844 i -1.0029074661 W3 = -0.94753965 Wy = 0.66105426 - 1.21107908 i of 13+4₁ | = 5 tan¹ (4/3)

e) C) modulus of d) Argument of 3+4i K = 0, 1, 2, 3, 4 roots for WK K (5) ½ se i (ton+ (1/3))/5 ws Wo Wo = 1.356069 + 0.25 4419 i W₁ = 0.177 08171 + 1.3683186 i W₂ = -1.2466 2713 + 0-59124844 i -1.0029074661 W3 = -0.94753965 Wy = 0.66105426 - 1.21107908 i of 13+4₁ | = 5 tan¹ (4/3)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Graph the following roots in linear form

e) c) d) K = 0, 1, 2, 3, 4 roots for WK Wo = (5) ³/5 i (ton²¹ (4/3))/5 Wo = 1.356069 + 0.25 4419 i W₁ = 0.177 08171 + 1.3683186 i W₂ = -1₁2466 2713 + 0-591248441 W3 94753965 1.002907466 i 0.66105426 - 1.21107908 i modulus of 13 +4₂²) Argument of 3+4i = - Wy = = 5 tan (4/3)
Transcribed Image Text:e) c) d) K = 0, 1, 2, 3, 4 roots for WK Wo = (5) ³/5 i (ton²¹ (4/3))/5 Wo = 1.356069 + 0.25 4419 i W₁ = 0.177 08171 + 1.3683186 i W₂ = -1₁2466 2713 + 0-591248441 W3 94753965 1.002907466 i 0.66105426 - 1.21107908 i modulus of 13 +4₂²) Argument of 3+4i = - Wy = = 5 tan (4/3)
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