In a DC circuit, the capacitor can be *replaced with a current sourcereplaced with an open circuitreplaced with a short circuitreplaced with a voltage sourceThe Inverse Laplace Transform for 1/S is *e^-atu(t)t^2For the Photoflash unit, Vs= 9V, R1=5KQ, C=1500 uf , R2= 120. The average powerdissipated by the lamp isR112Highvoltagede supply+vsR210W0.675W6.75W0.6W8.3WwwO O OOO O O OO OООО

Answered: Image /qna-images/answer/1a75d742-2fc6-43b9-8cb1-80d4a0195454.jpg

Answered: e^-at (1)n C Ot^2 For the Photoflash…

e^-at (1)n C Ot^2 For the Photoflash unit, Vs= 9V, R1=5KQ, C=D1500 uf , R2= 120. The average power dissipated by the lamp is * R1 1 2 High voltage de supply C R2 10W 0.675W 6.75W O0.6W

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Electrical Heating Unit

The conversion of electrical energy to heat energy is known as electric heating. The heating system that converts the electrical energy to heat energy for various application is called electrical heating unit. Electricity is employed as the firing mechanism in electric heating systems, which transforms electric current to heat. Electric heaters have heating elements in the form of electric resistors.

Question

In a DC circuit, the capacitor can be *
replaced with a current source
replaced with an open circuit
replaced with a short circuit
replaced with a voltage source
The Inverse Laplace Transform for 1/S is *
e^-at
u(t)
t^2
For the Photoflash unit, Vs= 9V, R1=5KQ, C=1500 uf , R2= 120. The average power
dissipated by the lamp is
R1
1
2
High
voltage
de supply
+
vs
R2
10W
0.675W
6.75W
0.6W
8.3W
ww
O O OO
O O O O
O O
ООО

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